0
Add your answer:
Earn +20 pts
What is 4x-x2?
4x-x2 = 2
What is X2 divided by -4x?
6
What is completely factored form?
A completely factored form is one which is composed of product of factors and can't be factorized further. Let us consider two examples: x2 - 4x + 4 is not a factored form because it can be factored as (x - 2)(x - 2). (x +1)(x2 - 4x + 4) is also not a factored form because x2 - 4x + 4 can be factored further as (x - 2)(x - 2). So, the completely factored form is (x + 1)(x - 2)(x - 2).
How do you factorise x2 plus 4x?
X2 + 4xx(x + 4)=======
What is the equivalent of the following equation y equals x2 - 8x plus 29?
The vertex form is y = (x - 4)2 + 13
What is the vertex form of y equals x2 plus 4x - 7?
The vertex of the positive parabola turns at point (-2, -11)
What are the coordinates of the vertex of y x2 - 4x - 5?
Y = X2 - 4X - 5set to zeroX2 - 4X - 5 = 0X2 - 4X = 5halve the linear term ( - 4 ) then square it and add that result to both sidesX2 - 4X + 4 = 5 + 4factor on the left and gather terms together on the right(X - 2)2 = 9(X - 2)2 - 9 = 0==============vertex form(2, - 9)======vertex
How do you calculate the vertex on a function graph?
Example function.Y = X2 - 4X + 5set to 0X2 - 4X + 5 = 0X2 - 4X = - 5Now, halve the linear coefficient, square it and add it to both sidesX2 - 4X + 4 = - 5 + 4gather terms on the right and factor on the left(X - 2)2 = -1==============Vertex form.(2, - 1)=======Vertex.
What is the equation of a parabola with the vertex of 2 -1?
3
What is the vertex of the graph of the function y equals x2-4x plus 3?
To find the extreme value of the parabola y = x2 - 4x + 3 ...(1) Take the derivative of the equation.y = x2 - 4x + 3y' = 2x - 4(2) Set the derivative = 0 and solve for x.y' = 2x - 40 = 2x - 42x = 4x = 4/2x = 2(3) Plug this x value back into the original equation to find the associated y coordinate.x = 2y = x2 - 4x + 3y = (2)2 - 4(2) + 3y = 4 - 8 + 3y = -1So the vertex is at (2, -1).
What is 4x-x2?
4x-x2 = 2
What is xsquared-4x plus 3 in standard from?
x2 - 4x + 3 is already in standard form.
What is the vertex of the parbola y equals x2-4x plus 12?
Differentiate and equate to zero Hence y = x^2 + 4x - 12 dy/dx = 2x + 4 = 0 2x = -4 x = -2 Hence y = (-2)^2 +4(-2) - 12 y = 4 - 8 - 12 y = - 16 Hence the vertex is (x,y,) = ( -2,-16)
What is X2 divided by -4x?
6
What is Y equals -3 plus 4x-x2 in standard form?
y=-x^2+4x-3
What are the factors of x2 - 4x?
-2
How do you find a vertex in quadratic function?
Easier to show you a simple example as I forget the formulaic approach. X2 + 4X - 6 = 0 add 6 to each side x2 + 4X = 6 Now, halve the linear term ( 4 ), square it and add it to both sides X2 + 4X + 4 = 6 + 4 gather the terms on the right side and factor the left side (X + 2)2 = 10 subtract 10 from each side (X + 2)2 - 10 = 0 (- 2, - 10 ) -------------------the vertex of this quadratic function
