Sum and difference of two cubes is factored this way : a3 + b3 = (a + b)(a2 - ab + b2) a3 - b3 = (a - b)(a2 + ab + b2)
(a + 4)(a^2 - 4a + 16)
This is the formula: (a3)+(b3)=(a+b)(a2-ab+b2)
(x3 - 8) is factored thus: (x - 2)(x2 + 2x + 4) The easiest way to do this is to remember the formula: (a3 - b3) = (a - b)(a2 + ab + b2)
a3-4a = a(a2-4) when factored
a(a^2 - 9a + 3)
A3+b3
(a - 1)(a^2 + a + 1)
the answer to factorising (a x a3 + 2ab + b2) would be (a4+2ab+b2)
kutta
Sum and difference of two cubes is factored this way : a3 + b3 = (a + b)(a2 - ab + b2) a3 - b3 = (a - b)(a2 + ab + b2)
Just choose the smaller exponent. The GCF of a3 and a5 is a3
First you can factor a^2 from the first two terms and 4 from the last two terms. (a^2)(a-2)+4(a-2) You can see that they both have (a-2) as a factor. So it is (a^2+4)(a-2)
(a+b)3=a3+b3+3ab(a+b) a3+b3=(a+b)3-3ab(a+b) a3+b3=(a+b)(a2-ab+b2)
The Answer:The sum of cubes, operation is: (a+b)(a2-ab+b2) = a3+b3So, since 27 = 33 we can reformulate to:So, x3+33 = (x + 3)(x2-3x+32) = (x + 3)(x2-3x+9).
(a + 4)(a^2 - 4a + 16)
The GCF is 1.