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6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90.

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βˆ™ 12y ago
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Anonymous

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βˆ™ 4y ago
Great
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βˆ™ 3mo ago

To find the sum of the first 15 multiples of 6, you can use the formula for the sum of an arithmetic series: ( \text{Sum} = \frac{n}{2} \times (a_1 + a_n) ), where ( n ) is the number of terms, ( a_1 ) is the first term, and ( a_n ) is the last term. In this case, ( n = 15 ), ( a_1 = 6 ), and ( a_n = 6 \times 15 = 90 ). Plugging these values into the formula gives ( \text{Sum} = \frac{15}{2} \times (6 + 90) = 15 \times 48 = 720 ). Therefore, the sum of the first 15 multiples of 6 is 720.

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Anonymous

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βˆ™ 4y ago

720

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That’s notntrue
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True

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Q: What is the sum of first 15 multiples of 6?
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5 + 10+15+20=50 ans


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To find the sum of the first 4 multiples of 6, you can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum, n is the number of terms, a1 is the first term, and an is the last term. In this case, the first 4 multiples of 6 are 6, 12, 18, and 24. Plugging these values into the formula, you get Sn = 4/2 * (6 + 24) = 2 * 30 = 60. Therefore, the sum of the first 4 multiples of 6 is 60.


The sum of three consecutive multiples of 6 is 666find the multiples?

The sum of three consecutive multiples of 6 is 666, the multiples are 216, 222 and 228.


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What is the sum of the first 6 multiples of 9?

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