6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90.
Chat with our AI personalities
To find the sum of the first 15 multiples of 6, you can use the formula for the sum of an arithmetic series: ( \text{Sum} = \frac{n}{2} \times (a_1 + a_n) ), where ( n ) is the number of terms, ( a_1 ) is the first term, and ( a_n ) is the last term. In this case, ( n = 15 ), ( a_1 = 6 ), and ( a_n = 6 \times 15 = 90 ). Plugging these values into the formula gives ( \text{Sum} = \frac{15}{2} \times (6 + 90) = 15 \times 48 = 720 ). Therefore, the sum of the first 15 multiples of 6 is 720.
The multiples of 3 are: 3, 6, 9, 12, 15, 18, 21, etc ...The multiples of 6 are: 6, 12, 18, 24, etc ...The multiples of 18 are: 18, 36, 54, etc ...The lowest multiple common to 3, 6, and 18 is 18, so the LCM = 18.
Set up an equation using x for the integer. The equation would be: x/(-4+6)=-15 Firstly find the sum of -4 and 6. It would be 2. The equation is now: x/2=-15 Multiply both sides by 2. This means that: x=-30 Plug it back into the equation to check: -30/(-4+6)=-15 -30/2=-15 -15=-15 It works therefore -30 is the integer that when divided by the sum of negative 4 and positive 6 equals negative 15.
4, 8, 12, 16, 20, 24.
24, 48, 72
15