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To find the sum of the first 15 multiples of 6, you can use the formula for the sum of an arithmetic series: ( \text{Sum} = \frac{n}{2} \times (a_1 + a_n) ), where ( n ) is the number of terms, ( a_1 ) is the first term, and ( a_n ) is the last term. In this case, ( n = 15 ), ( a_1 = 6 ), and ( a_n = 6 \times 15 = 90 ). Plugging these values into the formula gives ( \text{Sum} = \frac{15}{2} \times (6 + 90) = 15 \times 48 = 720 ). Therefore, the sum of the first 15 multiples of 6 is 720.
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What is the LCM of 3 and 6 and 18?
The multiples of 3 are: 3, 6, 9, 12, 15, 18, 21, etc ...The multiples of 6 are: 6, 12, 18, 24, etc ...The multiples of 18 are: 18, 36, 54, etc ...The lowest multiple common to 3, 6, and 18 is 18, so the LCM = 18.
What integer divided by the sum of negative 4 and positive 6 equals negative 15?
Set up an equation using x for the integer. The equation would be: x/(-4+6)=-15 Firstly find the sum of -4 and 6. It would be 2. The equation is now: x/2=-15 Multiply both sides by 2. This means that: x=-30 Plug it back into the equation to check: -30/(-4+6)=-15 -30/2=-15 -15=-15 It works therefore -30 is the integer that when divided by the sum of negative 4 and positive 6 equals negative 15.
First 6 multiples of 4?
4, 8, 12, 16, 20, 24.
What are the first three common multiples of 4 6 8?
24, 48, 72
3 consecutive even integers whose sum is -12?
15
What is the sum of the first 4 multiples of 5?
5 + 10+15+20=50 ans
What is the sum of the first 15 multiples of 3?
3+6+9...+45taking 3 common3(1+2+...+15) = 360
What is the sum of the first 5 multiples of 6?
90
What is the sum of the first three multiples of 6?
It is: 6+12+18 = 36
The sum of three consecutive multiples of 6 is 666find the multiples?
The sum of three consecutive multiples of 6 is 666, the multiples are 216, 222 and 228.
What is the sum of the first 2 multiples of 6?
1 x 6 = 62 x 6 = 12The sum of 12 + 6 = 18
The first 5 multiples of 3?
The first 5 multiples of 3 are as follows: 3, 6, 9, 12, 15
What is the sum of the first five multiples of 6?
6+12+18+24+30=90
What is the sum of the first 4 multiples of 6?
To find the sum of the first 4 multiples of 6, you can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum, n is the number of terms, a1 is the first term, and an is the last term. In this case, the first 4 multiples of 6 are 6, 12, 18, and 24. Plugging these values into the formula, you get Sn = 4/2 * (6 + 24) = 2 * 30 = 60. Therefore, the sum of the first 4 multiples of 6 is 60.
What does 6 multiples of 3 mean?
The first six multiples of 3 are 3, 6, 9, 12, 15, and 18.
What is the first multiples of 6 and 15?
6, 12, 18, 24 15, 30, 45, 60
What is the sum of the first 6 multiples of 9?
The first 6 multiples of 9 are 9, 18, 27, 36, 45 and 54. Their sum (total) is 189. In other words, 1x9 + 2x9 + 3x9 + 4x9 + 5x9 + 6x9 = 21x9 = 189.
