It is: y-5 = 2(x-1) => y = 2x+3
y = 4x - 26
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
Equation: y-3 = -5(x-6) => y = -5x+33
Points: (1, 2) and (0, -2) Slope: 4 Equation: y = 4x-2
The equation of a line with an undefined slope is x = a.
y = 4x - 26
y - 2 = 4(x - 7)
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
y+6=8(X+3) apex.
The equation of this line is x=8 and it is my understanding that the slope is infinite/undefined.
Coordinate: (1, 2) Slope: 4 Equation: y = 4x-2
The straight line equation is: y = mx+c whereas m is the slope and c is the y intercept
If you mean a slope of -5 and a point of (6, 3) then the equation is y = -5x+33
Slope: -5 Points: (6, 3) Equation: y = -5x+33
The equation of the line will also depend on its slope which has not been given and so an answer is not possible.
5
what is through (-3 , 2), slope -4 =