If you mean a point of: (2,1) then the equation works out as y = 3x-5
y-1 = 3(x - 2)
Slope: -3 Point: (4, -5) Equation: y = -3x+7
The answe iss..... 6
y=2x+1
using the point slope form: y - y1 = m (x - x1) y - 5 = 3 (x + 1)
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
Point: (2, -1) Slope: -5 Equation: y = -5x+9
y-1 = 3(x - 2)
The equation of the line will also depend on its slope which has not been given and so an answer is not possible.
y = 2x + 1
Slope: -3 Point: (4, -5) Equation: y = -3x+7
y=2x+13
y=3x-3
Slope 3 and point of (-1, 4)Equation: y-4 = 3(x--1) => y = 3x+7
The answe iss..... 6
y = 2x - 1
y=2x+1