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y = -x + 6

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Q: Write the equation of a line perpendicular to the line y x - 3 and containing the point 8 -2?
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Can you write the equation of a line with one point on the line?

No, you need either two points, one point and a slope, one point and a y-intercept, or a y-intercept an a slope. You can also write the equation of a line with an equation of another line but you would have to know if it is parallel or perpendicular.


What is perpendicular to y8x plus 3 and contains (57)?

If you mean: y = 8x+3 containing point (5,7) Then perpendicular equation is: y-7 = -1/8(x-5) => 8y = -x+61


How do you Write the equation of the line that is perpendicular to y 3x plus 8 and passes through the point (-3 4).?

If you mean y = 3x+8 then the perpendicular slope will be -1/3 and the equation works out as 3y = -x+9


Write the equation of the line through (2 3) that is perpendicular to y -2x - 2.?

If you mean: y = -2x -2 and point of (2, 3)Then perpendicular equation is: y-3 =1/2(x-2) => 2y = x+4


What is the equation of the line that contains the point (21) and is perpendicular to the line y3x-4?

If you mean: y=3x-4 and the point (2, 1) then the perpendicular equation is 3y=-x+5


Could you write the equation of the line that is perpendicular to the line given that passes through the point shown?

Yes, I could, if I knew the slope of the line given.


How do I write the equation of the line that passes through the given point and is perpendicular to the given line Write the answer in slope-intercept form?

The standard equation for a straight line is y = mx + c. Let this be the equation of the original line. Note that m and c are known values. Let the given point coordinates be (a,b)Two straight lines are perpendicular if the product of their gradients (slopes) is -1.The slope (m1) of the perpendicular line is therefore m1 = -1/mWhen y = b then x = a so the equation for the perpendicular line is y = m1x + d, and substituting gives : b = -a/m + d and this will enable d to be calculated.NOTE : In the absence of information for the equation of the original line and the coordinates of the given point then this is a general rather than a specific answer.


Write an equation of the line containing the given point and parallel to the the given line6 and 7 3x plus y equals 8?

Given point: (6, 7) Equation: 3x+y = 8 Parallel equation: 3x+y = 25


What equation describes a line that passes through the point (-14) and is perpendicular to the line 4x-3y-9?

If you mean point (-1, 4) and equation of 4x-3y = -9 then y = 4/3x+3 Slope of equation: 4/3 Perpendicular slope: -3/4 Perpendicular equation: y-4 = -3/4(x--1) => 4y = -3x+13


What is the equation of a line that is perpendicular to and passes through the point (8 3)?

That depends on the equation that it is perpendicular too which has not been given but both equations will meet each other at right angles.


What is the equation of a line that is perpendicular to and passes through the point (4 6)?

That would depend on its slope which has not been given.


What is the equation of a line that passes through the point 0 -3 and is perpendicular to a line with a slope of 4?

Perpendicular slope: -1/4 Perpendicular equation: y-0 = -1/4(x-3) => y = -0.25x+3