Suppose the equation is y = mx+c
The slope = m is 4 so y = 4x+c
(-2,1) lies on the line so substitute x=-2, y=1 into the equation of the line.
1 = 4*(-2)+c or 1 = -8+c or c = 9
So the equation is y = 4x + 9
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
Point: (2, 4) Slope: -3 Equation: y = -3x+10
Assuming the point is (9, -4), the equation is y = -4.
The equation is: y = 4x-22
It is: y-7 = -3(x--3) => y = -3x-2
sda
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
Point: (2, 17)Slope: 7Equation: y = 2x+13
Y=2x+6
(0,-6) m=-2
Y=mx+b
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
To write the point-slope equation of a line that passes through the point (5, 5), you need a slope (m) as well. The point-slope form is given by the equation ( y - y_1 = m(x - x_1) ). If the slope is not provided, you can express the equation generically as ( y - 5 = m(x - 5) ), where ( m ) is the slope of the line. If you have a specific slope, you can substitute it into the equation.
Point: (2, 4) Slope: -3 Equation: y = -3x+10
Yes, I could, if I knew the slope of the line given.
To write the equation of a line that is parallel to ( y = 23x - 2 ), you need to use the same slope, which is 23. The point through which the line passes is (-4, 7). You can use the point-slope form of the equation of a line: ( y - y_1 = m(x - x_1) ). Substituting in the slope (23) and the point (-4, 7), the equation becomes ( y - 7 = 23(x + 4) ), which simplifies to ( y = 23x + 99 ).
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.