(3x - y+ 2)(3x + y + 2)
(x + 3)(3x - 2)
Let the symbol ^ mean "to the power" Then 9x^2 + 24x + 16 = (3x + 4)(3x +4) = (3x + 4)^2
Step 1: Divide by 9x: 9x (x2 + 3x - 10) = 9x(x + 5)(x - 2)
10
3(x2 + 3x + 1)
(3x - y+ 2)(3x + y + 2)
(x + 3)(3x - 2)
Let the symbol ^ mean "to the power" Then 9x^2 + 24x + 16 = (3x + 4)(3x +4) = (3x + 4)^2
Step 1: Divide by 9x: 9x (x2 + 3x - 10) = 9x(x + 5)(x - 2)
(3x-4)(3x+4)
the answer is (3x-2)(9x squared+6x+4)
(3x + 8)(3x - 8)
(x + 2)(3x - 1)(3x + 1)
It is a difference of squares. 9x^2-49=(3x+7)(3x-7)
10
9x2...I guess that means 9x squared ? The problem: 9x(squared)+12x+4 Here's the answer: (3x+2)(3x+2) or even more simplified: (3x+2) squared