You can make 27 unique three-digit numbers using the three digits 0, 1, and 2.
i.e. for each of the three digits abc, there are 9 possible orders of those, from aaa to ccc.
The 9 starting with 0:
000
001
002
010
011
012
020
021
022
* the combinations are the same as the numbers 0 to 26 expressed in base 3 (000 to 222)
26 base 3 = 222 = 18 + 6 + 2 = 26
If the numbers are not repeated then the highest 5 digit even number to be made out of 0123456789 is : 98764.
This is easy. Just sort the digits in descending order. That works because the further left you go, the more significant the digit. So the largest number that can be made out of the digits 5, 3, 1, 4, and 7 is 75,431.
To find the smallest odd number that can be made using the numbers 4, 5, 3, and 6, we need to consider all possible combinations. The odd numbers that can be formed are 3 and 5. The smallest odd number would be 3, which can be formed using the numbers 3 and 6 by ignoring the digit 6.
Prime numbers cannot be made up from multiplying other numbers. Primary colours cannot be made up from adding other colours.
Introduction of the digit 0 as a place holder.
-4
1
6*7*7 = 294
24 three digit numbers if repetition of digits is not allowed. 4P3 = 24.If repetition of digits is allowed then we have:For 3 repetitions, 4 three digit numbers.For 2 repetitions, 36 three digit numbers.So we have a total of 64 three digit numbers if repetition of digits is allowed.
6 ways: 931,913,139,193,391,319
999
10
There are 900 natural numbers made up of only three digits. This is because there are 9 options for the first digit (1-9), 10 options for the second digit (0-9), and 10 options for the third digit (0-9). Multiplying these options together gives us 9 x 10 x 10 = 900 possible three-digit natural numbers.
999-111=888 888 3 digit numbers can be made with numbers between 1 - 9
It is a permutation problem (any number can be used repeatedly), it will become 4 x 4 x 4 x 4 = 256 four digit numbers. If each number can only be used once, then the answer is 4 x 3 x 2 x 1 = 24 four digit numbers.
To form a three-digit number using the digits 0-9, the first digit cannot be 0 (as it would not be a three-digit number). Thus, the first digit can be any of the digits from 1 to 9 (9 options). The second and third digits can each be any digit from 0 to 9 (10 options each). Therefore, the total number of three-digit numbers is (9 \times 10 \times 10 = 900).
If this is a homework assignment, please consider trying it yourself first, otherwise the value of the reinforcement to the lesson offered by the homework will be lost on you.There are 60 possibilities that can be made for a three digit number using the numbers 2 4 6 8 and 9. (5 choices for the first digit, 4 choices for the second digit, and 3 choices for the third digit - multiply 5, 4, and 3, and you get 60.)To determine how many of these three digit numbers are smaller than 500, consider that, given 2 4 6 8 and 9, the first digit would have to be 2 or 4. That gives 2 choices for the first digit, 4 choices for the second digit, and 3 choices for the third digit. Multiply 2, 4, and 3, and you get 24.