0 through 9 is 10 digits.
For the first number you have 10 choices, same for the second and third and forth, so your total amount of possible combinations (assuming you can repeat) is:
10 * 10 * 10 * 10 = 104 = 10,000 (ten thousand)
If repetition is not allowed, then for the first you have 10 choices, second you have 9 (every digit except the one you used for the first), third you have 8 and forth you have 7, giving you:
10 * 9 * 8 * 7 = 5040
place the digits 1 through 9 into three 3-digit numbers of an addition problem only using 1 through 9 once each
You can make 27 unique three-digit numbers using the three digits 0, 1, and 2.i.e. for each of the three digits abc, there are 9 possible orders of those, from aaa to ccc.The 9 starting with 0:000001002010011012020021022* the combinations are the same as the numbers 0 to 26 expressed in base 3 (000 to 222)26 base 3 = 222 = 18 + 6 + 2 = 26
Assuming each of the shirts is distinguishable from the others and similarly with the pants and a "combination" consists of one shirt and one pair of pants, the answer is 4*10 = 40 combinations.
You need to check whether they have a common factor. You can simply factor each of the numbers; for numbers that are much larger, using Euclid's algorithm is much faster.If the common factor of two numbers is greater than 1, then they are NOT relatively prime.
True. I think each and all mean the same thing in this context.
1000
There is only one combination. In a combination the order of the numbers does not matter so the only combination is 0123456789. This is the same as 1326458097
Each digit can appear in each of the 4 positions. There are 9 digits, therefore there are 9⁴ = 6561 such combinations.
It depends. If you can only use each number once, there are 720 combinations. If you can use numbers multiple times, then there are 1000 combinations, by using all numbers from 000 to 999.
35
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
10!/3! = 604800 different combinations.
There are 7 combinations. Each combination excludes a different one of the seven numbers.
In other words, how many 4 digit combination locks are there using the digits 0-9 on each wheel. There are 10×10×10×10 = 10⁴ = 10,000 such combinations.
There are ten combinations: one each where one of the ten digits, 0-9, is excluded.
137, 173, 317, 371, 713, 731 Six combinations can be made.
None. If you sellect three numbers each time, you can only get combinations of 3, 6, 9, ect but never 4. Also, there seems to be some confusion between people and numbers!