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What is the complex conjugate of -3-9i?
For any number (a + bi), its conjugate is (a - bi), so the real part stays the same, and the imaginary part is negated.For this one, conjugate of [-3 - 9i] is: -3 + 9i
Which is the correct notation for the complex number 113-square root-68?
113-2i sqr 17
What is the real part of the complex number -2i?
Ah, what a lovely question! When we have a complex number like -2i, we can see that the real part is 0. You see, the real part is the coefficient of the term with the variable "i," and in this case, there isn't a real part, so it's simply 0. Just a happy little zero floating peacefully in the complex plane.
When the sum of the complex numbers 3 plus 2I and 6 - 4I is graphed in which quadrant does it lie?
3+2i + 6-4i = 9-2i The real part of this number is positive, therefore it lies in Q1 or Q4. The imaginary part is negative, therefore it is in Q3 or Q4. Q4 is the common possibility, therefore 9-2i is in Q4.
Examples of complex numbers?
5+6i , -2-2i , 100+i.A complex number consists of a real part and an imaginary part: a+bi where 'i' is the imaginary unit (sq.rt(-1)).
What is 4-2i divided by 5-9i?
To solve this, you should multiply both terms of the division by (5 + 9i), using the rules of multiplication for complex numbers.
The conjugate of the complex number 3 plus 2i is?
It is 3 minus 2i
What is the complex conjugate of 8 plus 9i?
It would be 8 minus 9i or 8-9i
How do you divide complex numbers?
When dividing complex numbers you must:Write the problem in fractional formRationalize the denominator by multiplying the numerator and denominator by the conjugate of the denominator.You must remember that a complex number times its conjugate will give a real number.a complex number 2+2i. the conjugate to this is 2-i1. Multiply both together gives a real number.(2+2i)(2-2i) = 4 -4i + 4i + (-4i2) (and as i2 = -1) = 8To divide a complex number by a real number simply divide the real parts by the divisor.(8+4i)/2 = (4+2i)To divide a real number by a complex number.1. make a fraction of the expression 8/(2+2i)2. multiply by 1. express 1 as a fraction of the divisor's conjunction. 8/(2+2i)*(2-2i)/(2-2i)3. multiply numerator by numerator and denominator by denominator.(16-16i)/84. and simplify 2-2i
What is the complex conjugate of -3-9i?
For any number (a + bi), its conjugate is (a - bi), so the real part stays the same, and the imaginary part is negated.For this one, conjugate of [-3 - 9i] is: -3 + 9i
What is the magnitude of the complex number 8 plus 2i?
8.2462 (rounded)
What is conjugation of 7-2i?
The conjugate of a complex number can be found by multiplying the imaginary part by -1, then adding the "real" part back. (-2i) * -1 = 2i, so the conjugation is 7+2i
What is the magnitude of the complex number 3-9i?
Mag(3 - 9i) = sqrt(32 + 92) = sqrt(9 + 81) = sqrt(90) or 3*sqrt(10)
What is the complex conjugate of -12 over 2i-6?
2i+6
Is The sum of two complex numbers is sometimes a real number.?
Sure, if the imaginary part is opposite. For example:(3 + 2i) + (5 - 2i) = 8
Convert the following complex number into its polar representation: 2 + 2i?
2sqrt2(cos45 + i * sin45)
Can you figure out two complex numbers that when mulitplied together become a real number?
3 and 5 are both complex numbers, and if you multiply them together, you get 15, which is a real number. If you were looking for two non-real complex numbers, then any pair of complex conjugates will work. For example, 5+2i times 5-2i is 29.
