Oh, dude, the complex conjugate of 8 + 6i is just flipping the sign of the imaginary part, so it's 8 - 6i. It's like changing your mood from happy to grumpy, but in the world of math. So yeah, that's the deal with complex conjugates.
-6i-8
you must multiply by the conjagate. which is the denominator with the middle sign changed....(5+6i)...conjagate= (5-6i)....
5+6i , -2-2i , 100+i.A complex number consists of a real part and an imaginary part: a+bi where 'i' is the imaginary unit (sq.rt(-1)).
First, let's make sure we are not confusing imaginary numbers with complex numbers. Imaginary (sometimes called "pure imaginary" for clarity) numbers are numbers of the form ai, where a is a real number and i is the principal square root of -1. To multiply two imaginary numbers ai and bi, start by pretending that i is a variable (like x). So ai x bi = abi2. But since i is the square root of -1, i2=-1. So abi2=-ab. For example, 6i x 7i =-42. 5i x 2i =-10. (-5i) x 2i =-(-10)= 10. Complex numbers are numbers of the form a+bi, where a and b are real numbers. a is the real part, bi is the imaginary part. To multiply two complex numbers, again, just treat i as if it were a variable and then in the final answer, substitute -1 wherever you see i2. Hence (a+bi)(c+di) = ac + adi + bci + dbi2 which simplifies to ac-db + (ad+bc)i. For example: (2+3i)(4+5i) = 8 + 10i +12i + 15i2= 8 + 10i + 12i - 15 = -7 + 22i
The expression to simplify is 4+6i+7 Answer: 6i + 11
(4 + 6i)*(-7) = -28 - 42iAnd just because i = sqrt(-1), I am not something that you can multiply or simplify.
2.016022x10^6I think 'standard form' is 2,016,022 .
10 + 6i and 7 + 2i = 10 + 6i + 7 + 2i = 17 + 8i
6i
the problem: what is 4 + 4i + 4 + 6i what you do is add the real and imaginary parts, thus: 4+4 and 4i+6i = 8+10i answer.
Oh, dude, the complex conjugate of 8 + 6i is just flipping the sign of the imaginary part, so it's 8 - 6i. It's like changing your mood from happy to grumpy, but in the world of math. So yeah, that's the deal with complex conjugates.
Square root of 25 = +or- 5 Square root of -36 = +or- 6i where i is the imaginary number such that i^2=-1 Square root of 121 = +or-11 So the 8 possible answers are: -16-6i, -16+6i, -6-6i, -6+6i, 6-6i, 6+6i, 16-6i and 16+6i
2+6i
564
A complex number is x+iy and -6i is 0-6i or 0-i6 I would then answer yes.
-6i-8