Factor: x3 - 12x2 + 35x 1. Factor out a x: x(x2 - 12x + 35). 2. Factor x2 - 12x + 35 which is (x-5)(x-7). 3. Answer: x(x-5)(x-7).
x2 + 12x2 + 35 = 13x2 + 35 which cannot be factorised in any sensible way.
Factor out an X X(X^2 - 12X + 35) factor quadratic equation X(X - 7)(X - 5) ------------------- fully factored
x3 + 12x2 + 48x + 64= (x + 4)(x2 + 8x + 16)= (x + 4)(x + 4)(x + 4)= (x + 4)3
3X3 + 12X2 + 9X 3X(X2 + 4X + 3) 3X(X + 1)(X + 3) --------------------------------far as can be factored and you should see X intercepts of original function
12x2-x-35 = (4x-7)(3x+5)
x3 - 12x2 + 35x = x(x2 - 12x + 35) = x(x - 5)(x - 7)
x3 - 12x2 + 35x = x (x2 - 12x + 35) = x (x - 7) (x - 5)
Factor: x3 - 12x2 + 35x 1. Factor out a x: x(x2 - 12x + 35). 2. Factor x2 - 12x + 35 which is (x-5)(x-7). 3. Answer: x(x-5)(x-7).
x2 + 12x2 + 35 = 13x2 + 35 which cannot be factorised in any sensible way.
Factor out an X X(X^2 - 12X + 35) factor quadratic equation X(X - 7)(X - 5) ------------------- fully factored
x3 + 12x2 - 5x = x(x2 + 12x - 5) = x(x + 6 - √41)(x + 6 + √41)
x4 - 4x3 - 12x2 -32x + 64 (x - 4)(x + 2)(x + 2)(x - 4)
(4x + 5)(3x - 7)
The factors of 12x2 are 12 • x • x and the prime factors are 2 • 2 • 3 • x • x.
12x2+13x-35 = (4x-5)(3x+7) 12x2 + 13x- 35 let's find two factors of -420 (12*-35) whose sum is 13, which are 28 and -15 (12x + 28)(12x - 15) now simplify by 4 and 3 (3x + 7)(4x - 5)
x3 + 12x2 + 48x + 64= (x + 4)(x2 + 8x + 16)= (x + 4)(x + 4)(x + 4)= (x + 4)3