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Sorry cant help you, I assume this is missing '=' signs
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Jayson :)
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2x plus 3y equal 40 -2x plus 2y equal 20?
2x+3y=40-2x+2y=20Since 2x does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 2x from both sides.3y=-2xDivide each term in the equation by 3.(3y)/(3)=-(2x)/(3)Simplify the left-hand side of the equation by canceling the common terms.y=-(2x)/(3)if you were solving for x It would be x=-(3y)/2
How Do you Solve 2x-3y equals 2 3x plus 2y equals 3?
Given: 2x - 3y = 2 3x + 2y = 3 Take the first equation, and solve for x: x = (2 + 3y) / 2 Now plug it into the second equation: ∴ 3(2 + 3y) / 2 + 2y = 3 ∴ 3 + 9y/2 + 2y = 3 ∴ 9y/2 + 2y = 0 ∴ 22y = 0 ∴ y = 0 Then you can take that value of y, and plug it into either of our first equations to find x; 2x - 3y = 2 ∴ 2x - 3(0) = 2 ∴ 2x = 2 ∴ x = 1 So x is equal to one, and y is equal to zero.
What is the x- and y intercept of the linear function 2x - 3y equals 12?
2x - 3y = 12When x = 0, y = -4, so that y-intercept is -4.2x - 3y = 122(0) - 3y = 12-3y = 12 (divide both sides by -3)y = -4When y = 0, x = 6, so that x-intercept is 6.2x - 3y = 122x - 3(0) = 122x= 12 (divide both sides by 2)x = 6
X plus 3y equals 2 2X-3Y equals 22?
x + 3y = 2 2x - 3y = 22 Add the two equations: 3x = 24 Divide both sides by 3 to give x= 8. Substitue this value of x in the first equation to give 8 + 3y = 2 Subtract 8 from both sides: 3y = -6 Divide both sides by 3: y = -2 Solution: (X, y) = (8, -2)
What is the vertex of the graph of the function y equals x2-4x plus 3?
To find the extreme value of the parabola y = x2 - 4x + 3 ...(1) Take the derivative of the equation.y = x2 - 4x + 3y' = 2x - 4(2) Set the derivative = 0 and solve for x.y' = 2x - 40 = 2x - 42x = 4x = 4/2x = 2(3) Plug this x value back into the original equation to find the associated y coordinate.x = 2y = x2 - 4x + 3y = (2)2 - 4(2) + 3y = 4 - 8 + 3y = -1So the vertex is at (2, -1).
The line with equation 2x-3y equals 5 has slope?
Solve for y.2x - 3y = 52x - 2x - 3y = -2x + 5-3y = -2x + 5-3y/-3 = -2x/-3 + 5/-3y = (2/3)x - 3/5Clearly you see that the slope is 2/3.
How do you factor 12x2-27y2?
3(2x + 3y)(2x - 3y)
What is the slope of the line 2x-3y equals 5?
start with 2x - 3y = 5 add 3y to each side, 2x - 3y + 3y = 5 + 3y :: 2x = 5 + 3y subtract 5 from each side, 2x - 5 = 5 - 5 + 3y :: 2x - 5 = 3y divide each side by 3, (2x - 5)/3 = (3y)/3 :: (2/3)x - (5/3) = y the slope is the coefficient of "x" when the equation takes the form y = mx +b Therefore, the slope of the line is 2/3, approximately 0.667
How do you do this problem 2x plus 3y equals 1?
2x + 3y = 1 y = 1/3 - 2x/3
What is 2x-3y equals 6 converted to slope intercept form?
2x - 3y = 62x = 3y + 63y = 2x - 6y = (2x - 6)/3y = (2/3)x - 2
What is the equation of the line that passes through 2 3 and is parallel to 2x 3y 6?
If you mean: 2x+3y = 6 then it is 2x+3y = 11
How do you rewrite this equation so that y is a function of x 2x equals -3y plus 10?
2x = -3y + 10Add 3y to each side:2x + 3y = 10Subtract 2x from each side:3y = 10 - 2xDivide each side by 3:y = (10/3) - (2/3)x
What is the slope of the line 2x-3y equals 4?
2x-3y = 4 -3y = -2x+4 y = 2/3x-4/3 So the slope is 2/3 and the intercept is -4/3
2x plus 3y equal 40 -2x plus 2y equal 20?
2x+3y=40-2x+2y=20Since 2x does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 2x from both sides.3y=-2xDivide each term in the equation by 3.(3y)/(3)=-(2x)/(3)Simplify the left-hand side of the equation by canceling the common terms.y=-(2x)/(3)if you were solving for x It would be x=-(3y)/2
Is (1 1) a solution to 3y 2x 1?
Yes if you mean (1, 3) and 3y = 2x+1
What is the slope of 2x plus 3y equals 24?
2X + 3Y = 24 subtract 2X from both sides 3Y = - 2X + 24 divide both sides by 3 Y = - 2/3X + 8 slope(m) = - 2/3
Solve for y 2x plus 3y equals 11?
2x + 3y = 11Subract 2x from each side:3y = 11 - 2xDivide both sides by 3:y = 11/3 - (2/3)x
