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if y = x^3 +x^2+x-3, finding the roots of y can help. the roots are when x^3 +x^2+x-3 = 0, which x = 1 satisfies. Using something called Horner's method of synthetic division, (look it up, it's not too bad), you can take out the (x-1) and have (x-1)(x^2+2x+3) = 0, so either x - 1 = 0, x =1 (from before), or (x^2+2x+3) = 0, which you can factorise using quadratic methods to get x = (-2 (+or-) sqrt(4 - 12))/2 = 1 +- sqrt(2)i, so its not a pretty answer. involves complex numbers, I think this is right ayway .

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16y ago

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