Add numbers with the same signs: Number, Variable, and Variable Squared or another power.
Actually, since X is the same variable, cross both 2x and x2 out of the problem, then add 5 and 3.
x2 - 2x - 5 + 3
= x2 - 2x - 2
= (x2 - 2x + 1) -1 - 2
= (x - 1)2 - (√3)2
= (x - 1 - √3) (x - 1 + √3) you can rewrite it (if you want)
= [x - (1 + √3)][x - (1 - √3)]
(x + 7)(x - 5)
The question is ambiguous and two possible answers are given below: 2x2 - x2 = x2 or (2x)2 - x2 = 4x2 - x2 = 3x2
(x2 + 7x - 18) = (x + 9)(x - 2)
y = x2 + 2x + 1zeros are:0 = x2 + 2x + 10 = (x + 1)(x + 1)0 = (x + 1)2x = -1So that the graph of the function y = x + 2x + 1 touches the x-axis at x = -1.
4
x2+2x-120 = (x+12)(x-10) when factored
(2x3 - x2) = x2 (2x - 1)
X2 + 2X - 35 What two factors of - 35 add up to 2? (X - 5)(X + 7) -----------------
9x2 - 18x + 99(x2 - 2x + 1)==========
-x2+2x
Factor out a 22(X2 + X - 12)2(X - 3)(X + 4)===========
x2 + 2x - 15 = (x + 5)(x - 3)
(3x4 + 2x3 - x2 - x - 6)/(x2 + 1)= 3x2 + 2x - 4 + (-3x - 2)/(x2 + 1)= 3x2 + 2x - 4 - (3x + 2)/(x2 + 1)where the quotient is 3x2 + 2x - 4 and the remainder is -(3x + 2).
x3 + x2 - 6x + 4 = (x - 1)(x2 + 2x - 4)
16 + 6x - x2 = 16 + 8x - 2x - x2 = 8*(2 + x) - x*(2 + x) = (8 - x)*(2 + x)
It can be. x^2 + x + 1 is a factor of 2x^2 + 2x + 2
(x - 2)(x + 2)(x2 - 2x + 4)(x2 + 2x + 4)