Integrate 2sin(x)cos(x)dxLet u = cos(x) and du = -sin(x)dx and pull out the -2:-2[Integral(u*du)]Integrate with respect to u:-2(u2)/2 + CSimplify:-u2 + CReplace u with cos(x):-cos2(x) + C
Let us say that f(x)=x^4A derivative is the opposite to an integral.If you were to integrate x^4, the first process is taking the power [which in this case is 4], multiplying it by any value before the x [which is 1], then subtracting 1 from the initial power [4]. This leaves 4x^3. The final step is taking the integral of what is 'inside' the power [which is (x)], and multiplying this to the entire answer, which results in 4x^3 x 1 = 4x^3If you were to derive (x)^4, you would just add 1 to the power [4] to become (x)^5 then put the value of the power as the denominator and the function as a numerator. This leaves [(x^5)/(5)]To assure that the derivative is correct, integrate it. (x^5) would become 5x^4. Since (x^5) is over (5), [(5x^4)/(5)] cancels the 5 on the numerator and denominator, thus leaving the original function of x^4
The integral of cot(x)dx is ln|sin(x)| + C
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First see if the integrand ie x2-4 is negative anywhere in the range (it might change sign either side of anyplace where the function is zero, so first solve for x2-4=0). If it is, reverse the sign in that part. Here if x<2 it is negative so the modulus gives 4-x2. So integrate 4-x2 from 0 to 2 and then integrate x2-4 from 2 to 3. Add the 2 results together.
root x=x^(1/2) and 4x =4 x^1 you add the exponents then integrate as usual. The answer you should get is 4.
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x/sqrt(x)=sqrt(x) integral sqrt(x)=2/3x3/2
You will have to use partial fractions for this one. Split up the fraction into two simpler fractions, of the form A / x + B / (4-x). The result will be easy to integrate.
Yes. Let us use an example: x=1:10; % Data Set z=1:20; % Range y=x^2; % Equation equation1=trapz(y,z) % This will integrate y over the range of z for your data When integrating over a matrix: x2=[ 1 2 3; 4 5 6]; % Matrix y2=x*C; % Where c is any variable equation2=trapz(y2); % Will integrate over every column of your matrix and give you an array.
∫[√(4x) / x] dx = ∫(2 / √x)dx = 2∫(x-1/2) dx = 2(2x1/2 + C) = 4√x + C
e^x/1-e^x
4 is a constant, so you can pull it out of the integral. Use a u substitution with u = 3-x and du = -dx. If it's a definite integral, remember to change the limits of integration. The integral is then simply 1/u which integrates to be ln u. Substitute back in 3-x for u and you have the answer to be: -4*ln (3-x) + C
-(10/x)
x/4 - 4 = x/4 4x/4 - 4 x 4 = x x - 16 = x 0 = 16 There is no solution to the equation.
x/(x + 4) = 4/(x + 4) + 2 (x - 4)/(x + 4) = 2 x - 4 = 2x + 8 -x = 12 x = -12