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Despite my serious qualms with the wording of your question, I am assuming it to be the factoring of x2-2x+3
This is not factorable. As long as there is a positive 3 in the position of the constant element, there can only be -4 or 4 for the coefficient of the single x. Perhaps you made an error in entering the question, so I will provide some likely alternatives.
If the trinomial read as x2-2x-3, then it would be factorable and would be (x-3)(x+1)
If the trinomial read as x2-4x+3, then it would be factored as (x-3)(x-1)
If the trinomial read as x2+4x+3, then it would be factored as (x+3)(x+1)
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What are the factors of 2x squared plus 9x plus 9?
(2x+3)(x+3)
Factor 2x squared plus 8x plus 6?
2(x + 3)(x + 1)
X squared plus 2x - 15 equals 0?
x2 + 2x - 15 = 0(x + 5) (x - 3) = 0x = -5x = +3
Factor 8x cubed plus 4x squared plus 6x plus 3?
This is how I did it:8x3+4x2+6x+3[8x3+4x2]+[6x+3][(4x2)(2x+1)]+[(3)(2x+1)]....as you can see, this is in the general form of ab+cb, which factored is b(a+c), so:(2x+1)(4x2+3)
What is x-squared minus 2 x plus 15?
It is impossible but if it were x squared plus 2x minus 15 the equation would be (x+5) (x-3) with x being equal to either -5 or 3. If the original problem was x squared minus 2x minus 15 the equation would be (x-5)(x+3) and x would be equal to either 5 or -3
