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the answer is x(3+y)
6
y = 2 sin 3x y' = 2(sin 3x)'(3x)' y' = 2(cos 3x)(3) y' = 6 cos 3x
Get in function form. - 3X - Y = 4 - 1(- Y = 3X + 4) Y = - 3X - 4 ----------------------------solve for X and Y by the 0 out method - 3X - 4 = 0 - 3X = 4 X = - 4/3 --------------- Y = - 3(0) - 4 Y = - 4 -------------- Draw a line linking those points.
xy + y = z xy = z - y (xy)/y = (z - y)/y x = (z - y)/y
x(3 - y)
the answer is x(3+y)
21-7y+3x-xy7(3-y)+x(3-y)
Two terms of an expression
(y - 3)(x + 2y)
(x + 2)(y - 3)
y=1 and x=1 so 3(1)(1)=3 also you could say that xy=1 and that x=y
-1
1, 3, x, y, 3x, 3y, and xy are the factors of the expression 3xy
1,3,x,y,3x,3y,xy,3xy
6x - 2y + 3xz - yz = (z + 2)(3x - y) 9x - 3y = 3(3x - y) (3x - y) over (3x - y) equals 1, so they can be canceled out. The simplified expression is (z + 2) over 3.
y-3x-3 y=3x+3 A line with a slope of 3 crossing the y-axis at 3.