d/dx (e-x) = -e-x
e^(-2x) * -2 The derivative of e^F(x) is e^F(x) times the derivative of F(x)
2.71828183 ==So the derivative of a constant is zero.If you have e^x, the derivative is e^x.
-cos(x)
y = e^ln x using the fact that e to the ln x is just x, and the derivative of x is 1: y = x y' = 1
d/dx (e-x) = -e-x
-e^(-x) or negative e to the negative x this is because you multiply the function (e) by: 1 / (the derivative of the power ... in this case: -1) e^(-x) * (1/-1) = -e^(-x) Don't forget to add your constant!
e^(-2x) * -2 The derivative of e^F(x) is e^F(x) times the derivative of F(x)
The derivative of cos(x) is negative sin(x). Also, the derivative of sin(x) is cos(x).
2.71828183 ==So the derivative of a constant is zero.If you have e^x, the derivative is e^x.
The first derivative of e to the x power is e to the power of x.
1 divided by x to the third power equals x to the negative third. The derivative of x to the negative third is minus three x to the negative fourth.
-cos(x)
The derivative of ex is ex
e^[ln(x^2)]=x^2, so your question is really, "What is the derivative of x^2," to which the answer is 2x.
y = e^ln x using the fact that e to the ln x is just x, and the derivative of x is 1: y = x y' = 1
I suppose you mean of e-x? It is -e-x + C.