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sin(0)=0, therefore ysin(0)=0

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10y ago

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Y equals 4 sin x for x equals pi?

sin(pi) = 0 so 4*sin(pi) = 0 so Y = 0


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Y=sin X is a function because for each value of X, there is exactly one Y value.


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The value of sin(1) is 0.


What is the sin 180?

The sine of 180 degrees is 0. This is because, on the unit circle, the point corresponding to 180 degrees is located at (-1, 0), and the sine value represents the y-coordinate of that point. Therefore, sin(180°) = 0.


What is the y-intercept of y cscx?

The y-intercept of the function ( y = \csc(x) ) occurs when ( x = 0 ). Since ( \csc(x) = \frac{1}{\sin(x)} ), and ( \sin(0) = 0 ), ( \csc(0) ) is undefined. Therefore, the function ( y = \csc(x) ) does not have a y-intercept.


Find the value of y if sin y equals cos 48?

y = arcsin( cos 48 ); arcsin may be seen as sin-1 on your calculator.


What is the derivative of cos pi x plus sin pi y all to the 8th power equals 44?

(cos(pi x) + sin(pi y) )^8 = 44 differentiate both sides with respect to x 8 ( cos(pi x) + sin (pi y ) )^7 d/dx ( cos(pi x) + sin (pi y) = 0 8 ( cos(pi x) + sin (pi y ) )^7 (-sin (pi x) pi + cos (pi y) pi dy/dx ) = 0 8 ( cos(pi x) + sin (pi y ) )^7 (pi cos(pi y) dy/dx - pi sin (pi x) ) = 0 cos(pi y) dy/dx - pi sin(pi x) = 0 cos(pi y) dy/dx = sin(pi x) dy/dx = sin (pi x) / cos(pi y)


How do you solve 2 cos squared x plus sin x-1?

1


How do you find the amplitude maximum minimum and period for y equals -1 plus 3sin4x?

y = -1 + 3 sin 4xLet's look at the equation of y = 3 sin 4x, which is of the form y = A sin Bx, wherethe amplitude = |A|, and the period = (2pi)/B.So that the amplitude of the graph of y = 3 sin 4x is |3| = 3, which tell us that the maximum value of y is 3 and the minimum value is -3, and the period is (2pi)/4 = pi/2, which tell us that each cycle is completed in pi/2 radians.The graph of y = -1 + 3 sin 4x has the same amplitude and period as y = 3 sin 4x, and translates the graph of y = 3 sin 4x one unit down, so that the maximum value of y becomes 2 and the minimum value becomes -4.


When are y equals sin x and y equals cos x times cos x equal?

y=sin x y=cos x cos x sin x = cos^2 x sin x = 1-sin^2 x sin x -1 + sin^2 x = 0 sin^2 x + sin x -1 = 0 Let y=sin x y^2+y-1 = 0 This equation is of form ay^2+by+c=0 a = 1 b = 1 c = -1 y=[-b+/-sqrt(b^2-4ac)]/2a] y=[-1 +/-sqrt(1^2-4(1)(-1)]/(2)(1) discriminant is b^2-4ac =5 y=[-1 +√(5)] / 2 y=[-1 -√(5)] / 2 sin x = [-1 +√(5)] / 2 x = sin^-1 [-1 +√(5)] / 2] = 0.6662394 radians x = sin^-1 [-1 -√(5)] / 2] = sin^-1 (-1.618) -- has no solution When x = 0.6662394 radians, sin x and cos x times cos x are equal.


What is the value of x when y is 0?

if x:=x(y) then y=0 => x=x(0)


What is the sine of 180?

The sine of 180 degrees is 0. Remember, the sine value on a unit circle is the y-value. If you find f(pi) in the function f(x)=sin(x), you will get zero as an answer.