Yes, zero can and is the solution of many equations.
It is a linear equation in x. The equation has the solution x = 0.
A number that makes an equation true is a solution. If there is more than one answer to an equation (such as an equation like): (x-2)(x+4)=0 then it is called a solution set (and in this case would be x={-4, 2}).
It has infinitely many solutions.
Yes.
An equation with the solution set 1 and 3 can be written in factored form as (x-1)(x-3) = 0. When expanded, this equation becomes x^2 - 4x + 3 = 0. Therefore, the equation x^2 - 4x + 3 = 0 has the solution set 1 and 3.
r=0 is the solution...
An equation that is simplified to 0 0 is called a perfect equation. It usually have exactly one solution.
The equation 3m - 3m - 7 = 0, simplifies to -7 = 0 this means that the the solution is no solution, since -7 doesn't equal 0.
To determine if ( x^3 ) is a solution of the equation ( 3x - 54x = 0 ), we first simplify the equation. The left side simplifies to ( -51x = 0 ), which implies ( x = 0 ) is the only solution. Since ( x^3 ) is not equal to ( 0 ) for any ( x ) other than ( 0 ), ( x^3 ) is not a solution to the equation.
Only a linear equation in one variable x , which is an equation of the form ax + b = 0, (where a is different than 0), has only one solution. The solution is: x = -b/a
The simplest equation would be y4 = 0
Here is an example: x + 5 = 5If you subtract five from both sides, you get x = 0, which is an example of getting 0 as a solution for an equation.
Because without an equality sign it can not be considered to be an equation and therefore has no solution.
y - 7.0 = 0 is one possible equation.
root
How about x+4 = 0 ?
x = 00 reduces to x = 0/0. Both are undefined, and thus cannot be considered "equal". Other than that, nothing.