If a + b + c + d + 80 + 90 = 100, then a + b + c + d = -70.
d a tool for analysing c plus plus program
C=100, V=5, D=500
{ int a,b; { a=a^2; } { b=b^2; } { c=a^2+b^2+2*a*b; print f("%d%d%d",&c); get ch(); } ]
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a(c+d)+b(c+d)=(a+b)(c+d)
The reaction A plus B forms products C and D.
If a + b + c + d + 80 + 90 = 100, then a + b + c + d = -70.
If: a = b+c+d Then: c = a-b-d
(c + d)(c + d)
the answer is a
A B plus C plus D plus E plusorA B C D E plus plus plus plusor variations.
And how does this relate to coins?
int a=2, b=3, c=4, d=5; printf ("%d/%d + %d/%d = %d/%d\n", a, b, c, d, a*d+b*c, b*d);
d a tool for analysing c plus plus program
d2/(d - c) + c2/(c - d) = d2/(d - c) - c2/(d - c) = (d2 - c2)/(d - c) = (d + c)(d - c)/(d - c) = d + c
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