Q: What is the probability of the spinner landing on 1 or 4?

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The answer depends on the number of sides on the spinner and what numbers are on it.

The probability is one in four, or 25%.

It is 4/8 = 1/2

1/8 or .125 or 12.5%

You find out how many choices there are in a spinner and then you take what it wants you to find the probability of and tur it into a fraction For example: You have a spinner with 4 triangles in it....2 are red and 2 are green,What is the probability of landing on a green triangle 2 out of 4

The probability of landing on black twice on a spinner with white, black, and striped sections is (1/3)^2 = 1/9. This is because there is a 1/3 chance of landing on black on each spin, and the spins are independent events.

The depends on what other numbers exist on the spinner. If there are a total of six numbers on the spinner, for instance, the probability of spinning a 1-4 is 2 in 3.

Assuming that the four-sided spinner is fair and that it is numbered in the traditional way of 1, 2, 3 and 4, the probability of spinning a three is 1/4.

75% probability

Assuming each possible number on a spinner has the same probability and an unbiased die is being rolled, the answer depends on how many numbers are on the spinner, and how many times the number 4 appears on each.To find the probability, workout the probability of spinning a 4 on the spinner and the probability of rolling a 4 on the die; then as spinning the spinner has no effect on rolling the die, they are independent events and to get the probability of both happening multiply them together.The probability of success is the number of successful outcomes divided by the total number of outcomes, giving:Probability(spinning a 4) = how_many_4s_are_on_the_spinner / how_many_numbers_are_on_the_spinnerProbability(rolling a 4) = how_many_4s_are_on_the_die / how_many_numbers_are_on_the_dieProbability(spinning a 4 and rolling a 4) = Probability(spinning a 4) × Probability(rolling a 4)Examples:an octagonal spinner with the numbers 1-4 on it each twice and a tetrahedral die (as used in D&D games) with the numbers 1-4 on it→ pr(spin 4 & roll 4) = 2/8 × 1/4 = 1/16a decagonal spinner with the numbers 0-9 and a tetrahedral die with the numbers 0-3 on it→ pr(spin 4 & roll 4) = 1/10 × 0/4 = 0a decagonal spinner with the numbers 0-9 and a standard die with the numbers 1-6 on it→ pr(spin 4 & roll 4) = 1/10 × 1/6 =1/60

0.75%

The answer depends on the shape of the spinner and the numbers on it.