45,000 cm^2 * * * * * y = 0 is on the x-axis and you could not get much closer than that!
It is not true because the distance from (0, 0) to (2, 1) works out as the square root of 5 which is the circle's radius.
Center of circle: (2, 5) Point of contact with the x axis: (2, 0) Distance from (2, 5) to (2, 0) equals 5 which is the radius of the circle Equation of the circle: (x-2)^2 +(y-5)^2 = 25
Points: (-3, 2) and (7, 6) Slope: 2/5 Equation: 5y-2x = 16 x intercept: (-8, 0)
2X + 4Y = 8 The Y-intercept is the place where the line described by the equation crosses the Y-axis. But X=0 everywhere on the Y-axis. So at that point, 4Y = 8, and Y = 2. The X-intercept is the place where the line described by the equation crosses the X-axis. But Y=0 everywhere on the X-axis. So at that point, 2X = 8, and X = 4.
(x-a)^2+(y-0)^2=a^2 here the centre lies on x axis thus the centre wud be a point (a,0) and thus as it passes thru origin radius becomes a. as passes thru (0,0) LHS=(0-a)^2+(0-0)^2=a^2 RHS=a^2
The circles that have their centers on the y-axis are those that have the equation x^2 + (y-k)^2 = r^2, where k is the y-coordinate of the center of the circle and r is the radius of the circle. In this case, the x-coordinate of the center is 0 since it lies on the y-axis.
y = 5x - 2 This follows the general equation for a straight line y = mx + c. Where 'm' is the slope/gradient and 'c' is the y-intercept. At the point the line crosses the y-axis , then x = 0 Hence y = 5(0) - 2 y = -2 is the point the line intercept the y-axis.
On the 2-dimensional coordinate plane it is a point that is on the y-axis, two units of length away from the origin.
The point (8,0) is on an axis (abscissa axis or x-axis) and is therefore not in a quadrant.
45,000 cm^2 * * * * * y = 0 is on the x-axis and you could not get much closer than that!
The points are (-0.25, 0) and (0, 1)
In 2-d: (0, y) In 3-d: (0, y, 0) In 4-d: (0, y, 0, 0) and so on.
Of the points: (5, 3) (3, 0) (5, 2) and (0, 2) which means (x, y) thus the y values are 3, 0, 2 and 2 * * * * * True, but that does not answer the question that was asked. Only one of these points is on the y-axis and that is (0, 2).
4x2 + 25y2 = 100 (divide each element of both sides by 100) x2/25 + y2/4 = 1 This is the equation of an ellipse of the form x2/a2 + y2/b2 = 1, whose center is at (0, 0), a = 5, b = 2, and so c = √(a2 - b2) = √19) Since the major axis is horizontal and it lies on the x-axis, the vertices are 5 units to the left and 5 units to the right of the center (0, 0). Vertices are (-5, 0) and (5, 0). The minor axis is vertical and it lies on the y-axis, so the graph of the ellipse crosses the y-axis at the points (0, -2) and (0, 2), since b = 2) The foci are √19 units to the left and √19 units to the right of the center (0, 0). The foci are (-√19, 0) and (√19, 0).
They are the horizontal x axis and the vertical y axis that are perpendicular to each other on the Cartesian plane whereas the point of origin is at (0, 0)
The graph is a circle, with a diameter of 4, centered at the point (2, 0) on the x-axis.