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Using Pythagoras, the length of the side can be calculated:

Since it is a square, the two shorter lengths are the same, so:

2 x side2 = diagonal2

=> side = sqrt(diagonal2 / 2)

And once the side is known, the area can be calculated:

area = side2

= diagonal2 / 2

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Q: How do you find the area of a square whose diagonal length is 5 cm?
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