The formula for finding a line when the slope and y-intercept are known is as follows:
y = mx+b
If you know the slope and x-intercept, writing the equation to a line is easy. For example, if you know the x-intercept to be 3, and the slope to be 2, then you plug it into the equation y=mx+b. At the point where the line hits the x-intercept, the y-value is 0, meaning you actually have a data point (3,0). Plug this into your equation: 0=3(2)+b 0=6+b -6=b b=-6 Then you put the equation together, as you know m and b: y=2x-6
We can find m directly by looking at the change in vertical distance divided by the change in horizontal distance also know as the rise over the run. This give us m, the gradient. Anotther way is if we have the equation of the line, then the slope or gradient can be determined immediately from that. The equation of a line in slope-intercept from is y=mx+b and m represents the slope.
If you know the slope (m) and a point which we'll call x1, y1 then the equation of the line can be found by using the formula y - y1 = m(x - x1)Input the know values and then bring all the unknowns (x and y) to the left hand side and the knowns (the numbers) to the right hand side.For example:* Find the equation of the line that passes through the point (-2 , 5) and has a slope of -4. * Substitute y1 , x1 and m in the point slope form of a line * y - y1 = m(x - x1) * y - 5 = - 4(x - (-2))
Since we know the slope, m = 5/3, and the y-intercept 1/2, we arw able to write the equation of the line in the slope-intercept form, y = mx + b, so we have y = (5/3)x + 1/2.The standard form of the equation of the line is Ax + By = C.y = (5/3)x + 1/2y - y - 1/2 = (5/3)x - y + 1/2 - 1/2-1/2 = (5/3)x - y or(5/3)x - y = -1/2Thus, the standard form, Ax + By = C, of the equation of the line is (5/3)x - y = -1/2.
The slope of line AB will be 1/2. Two parallel lines will always have the same slope, so if you know the slope of one line that is parallel to another, you know the other line's slope.
i dont know 8x+5y=89
We know that the line passes through points (2, 2) and (0, 10) (since the y-intercept is 10).Using these two points, we can find the slope of the line,m = (10 - 2)/(0 - 2) = 8/-2 = 4/-1 = -4.Now by using the slope, m = -4, and the y-intercept, 10, we can write the equation of the line in the slope-intercept form, y = mx + b which isy = -4x + 10.
The slope of a curved line at a point is the slope of the tangent to the curve at that point. If you know the equation of the curve and the curve is well behaved, you can find the derivative of the equation of the curve. The value of the derivative, at the point in question, is the slope of the curved line at that point.
there is only one way i know how to find the slope of a hyperbola and that is taking the implicit derivative of its equation, and solving for dy/dx but the answer is Slope= (x)*(b^2) / (y)*(a^2)
If you know the slope of the line that your equation is perpendicular too, you find the negative reciprocal of it and use it as the slope for the line. (negative reciprocal = flip the slope over and change its sign. Ex: a slope of 2 has a negative reciprocal of -1/2. ) Then you use the given point, and put your equation in point-slope form. The general equation for point slope form is Y-y1=m(x-x1) The y1 is the y coordinate of the given point. X1 is the x coordinate of the given point. M is the slope that you found earlier. You now have your equation. If you are asked to put it in slope intercept form, simply distribute the numbers and solve the equation for y.
you should know this Find the difference of the y values over the difference in your x values to find the slope. Put it into the slope intercept form of the equation with one of the points substituted in and find the intercept. Rewrite the equation with the slope and the intercept. (-9-0)/(-3-0)=-9/-3=3 The slope. 27=3(9)+b 27=27+b 0=b Equation-> y=3x
First you subtract X from both sides. The equation then becomes Y = 7 - X. You can rewrite this as Y = -X + 7. Then the equation is in slope-intercept form Y = mx + b where m is the slope. By using this definition you can know that the coefficient attached to X is the slope. In the equation, X has a coefficient of -1 so the slope is -1.
yes because you will need the slope and y-intercept to find the equation of a line and the point through which the line passes is the y-intercept so it is yes!!!!!!! Good Luck!!!!!!!!!!!!!
If you know the slope and x-intercept, writing the equation to a line is easy. For example, if you know the x-intercept to be 3, and the slope to be 2, then you plug it into the equation y=mx+b. At the point where the line hits the x-intercept, the y-value is 0, meaning you actually have a data point (3,0). Plug this into your equation: 0=3(2)+b 0=6+b -6=b b=-6 Then you put the equation together, as you know m and b: y=2x-6
Slope Intercept form is meant for a line, so if you know the slope m in the equation y=mx+b then with a given point say (3,4) and say the slope of the line was 2 then the equation would read y=2x+4.
first you put the cone on a graph and if you know how to find slpoe rise/runlay it flatif you do not know how to get slope check out my other answer on how to get slope
There are a couple ways to determine the equation of a line without graphing. How to proceed depends on what you know about the line. Do you know a point, (x1, y1), and slope, m? Then use the point-slope formula, Do you know two points on the line, say (x1, y1) and (x2, y2)? Then use the two-point formula,