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How do you find the equation of a line if you know the slope and y-intercept?
Wiki User
∙ 14y ago
The formula for finding a line when the slope and y-intercept are known is as follows:
y = mx+b
- m is the slope
- b is the Y-intercept
Wiki User
∙ 14y ago
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How would you find the equation of a line if given the slope and x intercept?
If you know the slope and x-intercept, writing the equation to a line is easy. For example, if you know the x-intercept to be 3, and the slope to be 2, then you plug it into the equation y=mx+b. At the point where the line hits the x-intercept, the y-value is 0, meaning you actually have a data point (3,0). Plug this into your equation: 0=3(2)+b 0=6+b -6=b b=-6 Then you put the equation together, as you know m and b: y=2x-6
Formula to find gradient in co-ordinate geometry?
We can find m directly by looking at the change in vertical distance divided by the change in horizontal distance also know as the rise over the run. This give us m, the gradient. Anotther way is if we have the equation of the line, then the slope or gradient can be determined immediately from that. The equation of a line in slope-intercept from is y=mx+b and m represents the slope.
How do you find the equation of a line when given a containing point and slope?
If you know the slope (m) and a point which we'll call x1, y1 then the equation of the line can be found by using the formula y - y1 = m(x - x1)Input the know values and then bring all the unknowns (x and y) to the left hand side and the knowns (the numbers) to the right hand side.For example:* Find the equation of the line that passes through the point (-2 , 5) and has a slope of -4. * Substitute y1 , x1 and m in the point slope form of a line * y - y1 = m(x - x1) * y - 5 = - 4(x - (-2))
How do you find the standard form of a linear equation knowing only the y intercept and the slope IE A line has a slope of 5 over 3 and a y intercept of 1 over 2 State the equation in standard form?
Since we know the slope, m = 5/3, and the y-intercept 1/2, we arw able to write the equation of the line in the slope-intercept form, y = mx + b, so we have y = (5/3)x + 1/2.The standard form of the equation of the line is Ax + By = C.y = (5/3)x + 1/2y - y - 1/2 = (5/3)x - y + 1/2 - 1/2-1/2 = (5/3)x - y or(5/3)x - y = -1/2Thus, the standard form, Ax + By = C, of the equation of the line is (5/3)x - y = -1/2.
If AB is parallel to CD and the slope of CD is one over two what is the slope of AB?
The slope of line AB will be 1/2. Two parallel lines will always have the same slope, so if you know the slope of one line that is parallel to another, you know the other line's slope.
What would the equation of a line be if it went through the point 2 comma 2 and its yintercept was 10?
We know that the line passes through points (2, 2) and (0, 10) (since the y-intercept is 10).Using these two points, we can find the slope of the line,m = (10 - 2)/(0 - 2) = 8/-2 = 4/-1 = -4.Now by using the slope, m = -4, and the y-intercept, 10, we can write the equation of the line in the slope-intercept form, y = mx + b which isy = -4x + 10.
How does the slope of a linear equation differ from the slope of a quadratic equation?
i dont know 8x+5y=89
How the slope of a curved line at a point can be found?
The slope of a curved line at a point is the slope of the tangent to the curve at that point. If you know the equation of the curve and the curve is well behaved, you can find the derivative of the equation of the curve. The value of the derivative, at the point in question, is the slope of the curved line at that point.
What is the slope of a hyperbola?
there is only one way i know how to find the slope of a hyperbola and that is taking the implicit derivative of its equation, and solving for dy/dx but the answer is Slope= (x)*(b^2) / (y)*(a^2)
Find equation perpendicular to given line contain given point?
If you know the slope of the line that your equation is perpendicular too, you find the negative reciprocal of it and use it as the slope for the line. (negative reciprocal = flip the slope over and change its sign. Ex: a slope of 2 has a negative reciprocal of -1/2. ) Then you use the given point, and put your equation in point-slope form. The general equation for point slope form is Y-y1=m(x-x1) The y1 is the y coordinate of the given point. X1 is the x coordinate of the given point. M is the slope that you found earlier. You now have your equation. If you are asked to put it in slope intercept form, simply distribute the numbers and solve the equation for y.
What is the equation of the line containing the points (0, 0), (-3, -9), and (9, 27)?
you should know this Find the difference of the y values over the difference in your x values to find the slope. Put it into the slope intercept form of the equation with one of the points substituted in and find the intercept. Rewrite the equation with the slope and the intercept. (-9-0)/(-3-0)=-9/-3=3 The slope. 27=3(9)+b 27=27+b 0=b Equation-> y=3x
How would you find the slope in the problem Y plus X equals 7?
First you subtract X from both sides. The equation then becomes Y = 7 - X. You can rewrite this as Y = -X + 7. Then the equation is in slope-intercept form Y = mx + b where m is the slope. By using this definition you can know that the coefficient attached to X is the slope. In the equation, X has a coefficient of -1 so the slope is -1.
To find the equation of a line you must know at least one point through which the line passes and the slope of the line?
yes because you will need the slope and y-intercept to find the equation of a line and the point through which the line passes is the y-intercept so it is yes!!!!!!! Good Luck!!!!!!!!!!!!!
How would you find the equation of a line if given the slope and x intercept?
If you know the slope and x-intercept, writing the equation to a line is easy. For example, if you know the x-intercept to be 3, and the slope to be 2, then you plug it into the equation y=mx+b. At the point where the line hits the x-intercept, the y-value is 0, meaning you actually have a data point (3,0). Plug this into your equation: 0=3(2)+b 0=6+b -6=b b=-6 Then you put the equation together, as you know m and b: y=2x-6
How do you write an equation in slope intercept form with a given point?
Slope Intercept form is meant for a line, so if you know the slope m in the equation y=mx+b then with a given point say (3,4) and say the slope of the line was 2 then the equation would read y=2x+4.
How do you find the equation of a line without graphing?
There are a couple ways to determine the equation of a line without graphing. How to proceed depends on what you know about the line. Do you know a point, (x1, y1), and slope, m? Then use the point-slope formula, Do you know two points on the line, say (x1, y1) and (x2, y2)? Then use the two-point formula,
What is 3x - 4y equals 8 perpendicular to?
First, convert the equation to Slope-Intercept Form (y = mx + b) m = slope b = y-intercept 3x - 4y = 8 Subtract 3x from both sides of the equation. -4y = -3x + 8 Divide the entire equation by -4. y = 3/4x -2 Now that we know that the slope is 3/4, we can convert it to its perpendicular slope. The perpendicular slope is the opposite reciprocal of the original slope. In order to find it, we flip the fraction and change the sign. Original Slope: 3/4 Perpendicular Slope: -4/3
