0.5*(25-15) = 5 diagonals
Number of diagonals = 1/2*(n2-3n) where n = the number of sides of the polygon.
From each vertex, N-4 diagonals can be drawn, where N is the number of vertices. The total number of diagonals in a prism will be N(N-4)/2, where N is the number of vertices. For N=12 (a hexagonal prism) The total number of diagonals is 12*8/2=48 Answer:48
1/2*(n2-3n) = number of diagonals where n is the number of sides of the polygon.
5
There are two diagonals in a trapezoid.
It has 0 volume diagonals and 6 face diagonals hence the total number of diagonals are 6
number of diagonals = n(n-3)/2 n - number of sides of the polygon
The five sided Polygon has 5 diagonals
It has 20 diagonals
0.5*(25-15) = 5 diagonals
14 diagonals
Diagonals in an hexagon: 0.5*(6^2 -3*6) = 9 diagonals
The number of Diagonals in one vertex of a Triangle is 0 (zero)..
A 7 sided polygon has 14 diagonals
Number of diagonals = 1/2*(n2-3n) where n = the number of sides of the polygon.
Providing it's a regular polygon: 360/50 = 7.2 degrees