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Lenore Murphy
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∙ 15y agoy=1/2x-1
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Write the equation in slope intercept form for the line parallel to y equals 2 and with a y intercept of 3?
Start with the equation y = 2 Put that into slope-intercept form: y = 0x + 2 Change the y-intercept to 3 y = 0x + 3 or simply y = 3. This is a bit of a trick question to see if you understand the terminology. The line y = 2 is parallel to the x-axis, two spaces above it. A line parallel to that would also be parallel to the x-axis, and the intercept of 3 means that it is 3 spaces above the x-axis at the center of the graph. It remains 3 units above the x-axis out to infinity.
How would you find the equation of a line if given the slope and x intercept?
If you know the slope and x-intercept, writing the equation to a line is easy. For example, if you know the x-intercept to be 3, and the slope to be 2, then you plug it into the equation y=mx+b. At the point where the line hits the x-intercept, the y-value is 0, meaning you actually have a data point (3,0). Plug this into your equation: 0=3(2)+b 0=6+b -6=b b=-6 Then you put the equation together, as you know m and b: y=2x-6
How do find the slope of a line passing through points?
if you have a prob like Y=1X+-4 you would put the number next to 4 in fraction form, 1over1, then start at the origen and go to the Y intercept and move up1 right1 til you get to your point
How do you find slope-intercept form?
What is slope-intercept form?Slope intercept form of a line is y = mx +b. In the equation, m is the slope, and b is the y-intercept. (The line crosses the y-axis at the point (0,b)). For example, in the equation y = -(2/3)x - 5, the slope of the line is -2/3, and the line crosses the y-axis at the point (0,-5).The "solve for b" method(This can be used if you are given two points on a line.)The formula for slope intercept is y = mx + b.m is the slopeFirst you need to find the slope of the line (m). The formula for slope is(y2-y1)/(x2-x1).For example, let's take the points (3, -2) and (5,1). The slope would be(1 - -2)/(5-3), which is 3/2, which is 11/2or 1.5. For this problem, we will leave it as an improper fraction, so m, or the slope, is 3/2.Now we have y = (3/2)x + b.b is the y-intercept, or the point where the line crosses the x-axis. (The line crosses the x-axis at the point (0,b). b is the number we need to find next.In order to find b, plug in one of the original points for x and y. In this example, we will use the point (5,1). (You could use (3,-2) if you wanted to.) When we plug in the point (5,1), we will get:1 = 5(3/2) + bSolve for b: First combine like terms:1 = 15/2 + bSubtract 15/2 from each side:-13/2 = bWe have now found out that b = -13/2. so the complete formula for a line that passes through (3,-2) and (5,1) is:y = (3/2)x - 13/2(You could also write it as y = 1.5x - 6.5)(Below is another method)The point-slope to slope intercept method:(This can be used if you are given two points on a line.)First you write it in point slope form and then convert it to slope intercept y=mx+b form.Point-Slope form is y-y1 = m(x-x1)m is the slopeIn this example, we will use the points (3, -2) and (5,1), to show that both methods arrive at the same answer.To start, calculate the slope, (the same way as above):The formula for slope is(y2-y1)/(x2-x1).The slope would be (1 - -2)/(5-3), which is 3/2, which is 11/2or 1.5. We will leave it as an improper fraction, so m, or the slope, is 3/2.Next, plug in one of the points into x1 and x2­ in the point slope equation. In this example, the point (5,1) is used. Now, we have:y - 1 = (3/2)(x- 5)Now, the equation needs to be put into the form y = mx + bFirst, distribute:y-1 = (3/2)x - 15/2Next, add 1 to each side:y = (3/2)x -13/2The final answer is y = (3/2)x - 13/2, which can also be written as y = 1.5x - 6.5How to find slope-intercept form if you are given the equation of a line in standard form:The formula for standard form is ax + by + c. You are converting this to slope intercept form, which is y = mx + b. This process is a matter of using algebra. Here is an example: Convert the line 3x + 5y = 25 to slope intercept form:3x + 5y = 25First, the x must be moved to the other side, so we will subtract 3x from both sides:5y = 25 - 3xIn order to match the formula y = mx + b, the terms 25 and -3x need to be switched around:5y = -3x + 25Remember to keep the negatives signs in front of their terms when you move them around!Now, both sides of the equation need to be divided by 5. (All 3 terms must be divided by 5):(5/5)y = -(3/5)x + (25/5)After simplifying the fractions, the final equation isy = -(3/5)x + 5So, the line 3x + 5y = 25 is y = -(3/5)x + 5 in slope-intercept form. (This can also be written as y = -.6x + 5)How to find slope-intercept form if you are given the equation of a line in point-slope form:Point-slope form of a line is y-y1 = m(x - x1). You are converting this to slope intercept form, which is y = mx + b. This process is a matter of using algebra. Here is an example: Convert the liney - 5 = (2/3)(x+4) to slope intercept form:y - 5 = (2/3)(x+4)First, distribute the terms the right side of the equation:y - 5 = (2/3)x + (2/3)(4)After simplifying, the equation isy - 5 = (2/3)x + (8/3)(8/3) can be rewritten as 22/3:y - 5 = (2/3)x + 22/3Now, add five to each side of the equation:y = (2/3)x + 72/3So, the equation y - 5 = (2/3)(x+4) is y = (2/3)x + 72/3 in slope-intercept form. (This can also be written as y = (2/3)x + 23/3 or y = (2/3)x + 7.666)How to find slope-intercept form if you are given the graph of a line:The first thing to do is pick two points on the line that are at whole numbers, (such as (2,3) and (4,7)). If you can't find two points at whole numbers, you can estaimate where you think a point on that line is, and use those. (For example, you may see a point on the line around (1,2.5).)Once you have found those two points, you can use one of the methods above, either the "solve for b" method or the "point-slope to slope intercept method". You can also use the visual method below:In this example, we will find the formula of a line that passes through the points (2,3) and (4,7). (It may help to draw out the line so that you can better visualize this example.) First, we will find the slope using the "rise over run: method. If you put your finger on the point (2,3), you will need to go four spaces to get level with the point (4,7). So 4 is your "rise". You will need to go right 2 spaces to get to the point (4,7), so 2 is your run. The line climbs so the slope is positive. (If the line were to drop, such as a line that passed through the points (1,1) and (0,2), the slope would be negative.) Now you have found that your "rise" is 4, your "run" is 2, and the slope is positive. The slope is "rise over run", which, in this case, is 4/2, which can be simplified to 2. In the equation y = mx + b, m is the slope, so we now havey = 2x + band we need to find b. b is the point where the line crosses the y-axis. You may be able to see that the line in this example crosses the y-axis at the point (0,1), so in this case b is 1. (If the line had crossed the y-axis at (0,-5), b would have been -5). Now we have the complete equation:y = 2x + 1So, the equation of the line that passes through the points (2,3) and (4,7) is y = 2x + 1.
How do you graph Slope intercept form y4x 9?
Well, that isn't a proper equation but if the equation is, y=4x(+/-)9... First: Put the "b" value into your graph. The "b" value is on the y-intercept, in this case, it would be (+/-)9. If it is +9, put it 9 values up on the y-axis. Vice-versa if negative. Second: The 4x would be the slope. The 4 represents the "a or m" value. Since the slope is 4, then you would start at the (+/-)9 and go UP:4 and OVER:1. This is the Rise Over Run technique. The reason you go over 1 is because 4=4/1 the 4 represents rise and the 1 represents run. (If the "m"value was 1/4 then you'd go up 1 and over 4). Lastly: Repeat that method over and over again until you run out of room on your graph. Then make a line connecting each dot and at the end of each line put arrows pointing outward displaying that the slope will be infinite.
Slope-intercept form of the line that has a slope of 7 and y-intercept of 1?
6
Slope-intercept form of the line that has a slope of -5 and a y-intercept of 2?
-7
Slope-intercept form of the line that has a slope of 2 and y-intercept of -2?
4
Slope-intercept form of the line that has a slope of -7 and y-intercept 6?
-13
Slope-intercept form of the line that has a slope of 5 and y-intercept of -3?
8
Slope-intercept form of the line that has a slope of -2 and y-intercept of 2?
-4
What is the slope intercept form of the equation of a line with a slope 2 and a y intercept of -4?
6
How the you Write the equation in slope-intercept form of the line that has a slope of 2 and y-intercept of -2?
slope-intercept from is y=mx+b, m is the slope and b is the y-intercept. put the values of the slope and y-intercept into the equation. y=2x-2
Find the equation of the line in slope intercept form slope 3 y-intercept -4?
slope intercept form is y=mx+bm=slopeb= y-interceptjust simply put what you have in that equationy = 3x - 4
Can The equation of a line can be put in to the slope-intercept form?
Yes normally
What is 3x-2y equals 16 in slope intercept form?
The slope-intercept form of the equation of a line is y = mx + b, where m is the slope and b is the y-intercept. To put 3x - 2y = 16 in slope-intercept form just requires a little rearranging: 3x - 2y = 16 -2y = -3x + 16 (subtract 3x from both sides) y = 3/2x - 8 (divide all terms by -2) Now the equation is in slope-intercept form. The slope m is 3/2; the y-intercept is -8.
Can the equation of a line sometimes be put in to the slope-intercept form?
Always. Any equation can be put into slope intercept form. Take x+5y=16, for example. This would be changed into y=16/5 + x/5.
