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y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
If you have any expression that defines a line, you can find the slope of the line. After you have found the slope of the line, you can then write an expression describing the line in slope intercept form. You can't define a slope-intercept form for any nonlinear equation, because the slope is always* changing; there are often several intercepts as well.
When it is a line through the origin.
It is: y = mx+b whereas m is the slope and b is the y intercept
We usually denote the slope of a line as M. Horizontal lines have a slope of zero. Mhorizontal line = 0 Verticle lines have a slope that is undefined. Note that the slope is not infinite, but is undefined. Mvertical line = undefined To write the equation of a horizontal or vertical line, we need to know if it's going to be a slope-intercept form or a point-slope form.
y = 2x + 1.
You can write it either in standard form (ax + by = c) or in slope-intercept form (y = mx + b)
Without the inclusion of an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be a straight line equation
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3
If you have any expression that defines a line, you can find the slope of the line. After you have found the slope of the line, you can then write an expression describing the line in slope intercept form. You can't define a slope-intercept form for any nonlinear equation, because the slope is always* changing; there are often several intercepts as well.
Get the slope of the given line, by putting it into slope-intercept form. Then you can divide minus one by this slope, to get the slope of any perpendicular line.
The equation of a line in slope-intercept form is given by y = mx + b, where "m" represents the slope of the line and "b" represents the y-intercept.
We know that the line passes through points (2, 2) and (0, 10) (since the y-intercept is 10).Using these two points, we can find the slope of the line,m = (10 - 2)/(0 - 2) = 8/-2 = 4/-1 = -4.Now by using the slope, m = -4, and the y-intercept, 10, we can write the equation of the line in the slope-intercept form, y = mx + b which isy = -4x + 10.
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The slope of a vertical line is undefined and so there cannot be a slope-intercept form of the equation.
When it is a line through the origin.