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Write the equation in slopeintercept form of the line that has a slope of 3 and contains the point 2 5?
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
How do you write an equation in slope intercept form if there is no slope?
If you have any expression that defines a line, you can find the slope of the line. After you have found the slope of the line, you can then write an expression describing the line in slope intercept form. You can't define a slope-intercept form for any nonlinear equation, because the slope is always* changing; there are often several intercepts as well.
What form to use when you know the slope of the line and one of the points on the line?
When you know the slope of the line and one of the points on the line, you can use the point-slope form of the equation of a line. This is expressed as (y - y_1 = m(x - x_1)), where (m) is the slope and ((x_1, y_1)) is the known point on the line. This form is particularly useful for easily writing the equation when you have both the slope and a specific point.
When does the equation of a line in slope-intercept form look just like its equation in point-slope form?
When it is a line through the origin.
What is the general form of a line written in slope-intercept form?
It is: y = mx+b whereas m is the slope and b is the y intercept
Write the equation in slopeintercept form of the line that has a slope of 2 and contains the point 3 7?
y = 2x + 1.
How do you write an equation of a line that passes through the xintercep and yintercept?
You can write it either in standard form (ax + by = c) or in slope-intercept form (y = mx + b)
What are the slope and yintercept of line 5x 10y 15?
Without the inclusion of an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be a straight line equation
Write the equation in slopeintercept form of the line that has a slope of 3 and contains the point 2 5?
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
Write the equation in slopeintercept form of the line that has a slope of 3 and contains the point 4 9?
The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3
How do you write an equation in slope intercept form if there is no slope?
If you have any expression that defines a line, you can find the slope of the line. After you have found the slope of the line, you can then write an expression describing the line in slope intercept form. You can't define a slope-intercept form for any nonlinear equation, because the slope is always* changing; there are often several intercepts as well.
What is the slope of a line that is perpendicular to the line whose equation is 2y x - 1?
Get the slope of the given line, by putting it into slope-intercept form. Then you can divide minus one by this slope, to get the slope of any perpendicular line.
What would the equation of a line be if it went through the point 2 comma 2 and its yintercept was 10?
We know that the line passes through points (2, 2) and (0, 10) (since the y-intercept is 10).Using these two points, we can find the slope of the line,m = (10 - 2)/(0 - 2) = 8/-2 = 4/-1 = -4.Now by using the slope, m = -4, and the y-intercept, 10, we can write the equation of the line in the slope-intercept form, y = mx + b which isy = -4x + 10.
What is the equation in slope-intercept form of the line that has a slope of 5 and y-intercept of -3?
8
What is the equation of a line in slope-intercept form?
The equation of a line in slope-intercept form is given by y = mx + b, where "m" represents the slope of the line and "b" represents the y-intercept.
What is the slope intercept form when a vertical line is passing through 5 -8?
The slope of a vertical line is undefined and so there cannot be a slope-intercept form of the equation.
When does the equation of a line in slope-intercept form look just like its equation in point-slope form?
When it is a line through the origin.
