There needs to be more information to this question. It needs to explain what A and B are before it can be answered.
B is (-5, 9).
a = (-2,3)b = (5,-4)vector AB = b - a = (7,-7)Length of AB = sqrt( 72 + 72) = sqrt(98) = 7*sqrt(2)Midpoint of AB = a + (b-a/2) = (-2,3) + (7/2,-7/2)= (3/2,-1/2)
this is a continuation of the question... AB=4, BC=6, AE=8, and BE intersects at D
AB and BC are both radii of B. To prove that AB and AC are congruent: "AC and AB are both radii of B." Apex.
Zero.For instance, given a right triangle with points ABC. where AC is the hypotenuse, then to find the angle between AB, we take sin(AB/AC), where AB is the distance between points A and B, and AC is the distance between A and C. If we replace AB with 0, the equation would be sin(0/AC). Sine of zero is always zero.
Find ab
oh my goodness not even dr.sheldon cooper can answer that
To determine the coordinates of point D in trapezium ABCD, we need the coordinates of points A, B, and C, as well as the requirement that one pair of opposite sides (either AB and CD or AD and BC) are parallel. If AB is parallel to CD, then the y-coordinates of points A and B must equal the y-coordinates of points C and D, respectively. Alternatively, if AD is parallel to BC, then the x-coordinates of A and D must equal the x-coordinates of B and C. Please provide the specific coordinates of points A, B, and C for a precise answer.
To find the distance AB between points A and B on a number line, you can use the formula ( AB = |A - B| ). Given that the coordinates of A and B are ( \sqrt{27} ) and ( \sqrt{15} ) respectively, we calculate ( AB = |\sqrt{27} - \sqrt{15}| ). Simplifying, this results in ( AB = |\sqrt{27} - \sqrt{15}| \approx |5.196 - 3.873| \approx 1.323 ). Thus, the distance AB is approximately 1.323.
ab = sqrt(27) - sqrt(15) = sqrt(3)*3 - sqrt(3)*sqrt(5) = sqrt(3)*(3 - sqrt(5)) and that cannot be simplified further.
B is (-5, 9).
It takes two coordinates to locate one point, but you've given only two numbers to locate two points. The distance between them can't be calculated with the information given, because the points can't be identified.
A & B + respectively
If point a has coordinates (x1,y1), and point b has coordinates (x2, y2), then the slope of the line is given by the formula: m = (y2-y1)/(x2-x1).
The coordinates of point B can be calculated using the midpoint formula. The midpoint formula is used to find the midpoint of two points, and is calculated by taking the average of the x-coordinates and the average of the y-coordinates. In this case, we are given the midpoint of AB, which is (-2, -4). We also know the coordinates of point A, which are (-3, -5). Using the midpoint formula, we can calculate the x-coordinate of point B by taking the average of the x-coordinates of points A and M. This is (-3 + -2)/2 = -2.5. We can calculate the y-coordinate of point B in a similar way. This is (-5 + -4)/2 = -4.5. Therefore, the coordinates of point B are (-2.5, -4.5).
a = (-2,3)b = (5,-4)vector AB = b - a = (7,-7)Length of AB = sqrt( 72 + 72) = sqrt(98) = 7*sqrt(2)Midpoint of AB = a + (b-a/2) = (-2,3) + (7/2,-7/2)= (3/2,-1/2)
Here is a proof. Let a and b be any two real numbers. Consider the number x defined as x = ab + (-a)(b) + (-a)(-b). We can write this out differently as x = ab + (-a)[ (b) + (-b) ] Then, by factoring out -a , we find that x= ab + (-a)(0) = ab + 0 = ab. Also, x = [ a + (-a) ]b + (-a)(-b) And by factoring out b, we find that x=0 * b + (-a)(-b) = 0 + (-a)(-b) = (-a)(-b). Therefore x = ab and x = (-a)(-b) Then, by the transitivity of equality, we have ab = (-a)(-b).