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M is the midpoint of line segment AB. A has coordinates (3-7) and M has coordinates (-11). What is the coordinates of B?
B is (-5, 9).
Find the length of AB and the coordinates of its midpoint Point A is plotted as -2X and 3Y Point B is plotted as 5X and -4Y?
a = (-2,3)b = (5,-4)vector AB = b - a = (7,-7)Length of AB = sqrt( 72 + 72) = sqrt(98) = 7*sqrt(2)Midpoint of AB = a + (b-a/2) = (-2,3) + (7/2,-7/2)= (3/2,-1/2)
Suppose that point A has coordinates 0 0 Point B would then have coordinates 4 0 and so on Find the areas of the three smaller triangles in the picture angle EAB and angle ABC are right angles.?
this is a continuation of the question... AB=4, BC=6, AE=8, and BE intersects at D
In the straightedge and compass construction of an equilateral triangle below which of the following reasons can you use to prove that and are congruent?
AB and BC are both radii of B. To prove that AB and AC are congruent: "AC and AB are both radii of B." Apex.
If AB equals 0 what is the angle between a and b?
Zero.For instance, given a right triangle with points ABC. where AC is the hypotenuse, then to find the angle between AB, we take sin(AB/AC), where AB is the distance between points A and B, and AC is the distance between A and C. If we replace AB with 0, the equation would be sin(0/AC). Sine of zero is always zero.
The coordinates of a and b are square root of 27 and square root of 15 reapectively find ab?
Find ab
When point A has coordinates 65 and the point B has coordinates 2-1 find the coordinates of the midpoint of AB?
oh my goodness not even dr.sheldon cooper can answer that
The coordinates of a and b are the square root of 27 and the square root of 15 respectively find ab?
ab = sqrt(27) - sqrt(15) = sqrt(3)*3 - sqrt(3)*sqrt(5) = sqrt(3)*(3 - sqrt(5)) and that cannot be simplified further.
M is the midpoint of line segment AB. A has coordinates (3-7) and M has coordinates (-11). What is the coordinates of B?
B is (-5, 9).
The coordinates of A and B are 27 square root and 15 square root respectively Find AB?
It takes two coordinates to locate one point, but you've given only two numbers to locate two points. The distance between them can't be calculated with the information given, because the points can't be identified.
Find slope of the line ab?
If point a has coordinates (x1,y1), and point b has coordinates (x2, y2), then the slope of the line is given by the formula: m = (y2-y1)/(x2-x1).
What type blood do parents have to have for their child to have ab positive blood?
A & B + respectively
The midpoint of ab is m (-2, -4) if the coordinates of a are (-3, -5) what are the coordinates of B?
The coordinates of point B can be calculated using the midpoint formula. The midpoint formula is used to find the midpoint of two points, and is calculated by taking the average of the x-coordinates and the average of the y-coordinates. In this case, we are given the midpoint of AB, which is (-2, -4). We also know the coordinates of point A, which are (-3, -5). Using the midpoint formula, we can calculate the x-coordinate of point B by taking the average of the x-coordinates of points A and M. This is (-3 + -2)/2 = -2.5. We can calculate the y-coordinate of point B in a similar way. This is (-5 + -4)/2 = -4.5. Therefore, the coordinates of point B are (-2.5, -4.5).
What blood types can be formed by crossing A genes with B genes?
If the parent's blood type is A and B, respectively, the possible blood type of their child are A, AB, B and O.
Find the length of AB and the coordinates of its midpoint Point A is plotted as -2X and 3Y Point B is plotted as 5X and -4Y?
a = (-2,3)b = (5,-4)vector AB = b - a = (7,-7)Length of AB = sqrt( 72 + 72) = sqrt(98) = 7*sqrt(2)Midpoint of AB = a + (b-a/2) = (-2,3) + (7/2,-7/2)= (3/2,-1/2)
Why is a negative times a negative a positive?
Here is a proof. Let a and b be any two real numbers. Consider the number x defined as x = ab + (-a)(b) + (-a)(-b). We can write this out differently as x = ab + (-a)[ (b) + (-b) ] Then, by factoring out -a , we find that x= ab + (-a)(0) = ab + 0 = ab. Also, x = [ a + (-a) ]b + (-a)(-b) And by factoring out b, we find that x=0 * b + (-a)(-b) = 0 + (-a)(-b) = (-a)(-b). Therefore x = ab and x = (-a)(-b) Then, by the transitivity of equality, we have ab = (-a)(-b).
How do you find a point that is collinear with four points?
The answer depends on the information that you have about the four points and the manner in which that information is presented. Suppose the 4 points are A, B, C and D and the point that you find is P. If you have the coordinates of A, B, C and D then gradient AP = gradient AB (or any other pair) will suffice. If you have any one of vectors AB (or AC, AD, BC, BD), then vector AP is parallel to vector AB will suffice.
