B is (-5, 9).
a = (-2,3)b = (5,-4)vector AB = b - a = (7,-7)Length of AB = sqrt( 72 + 72) = sqrt(98) = 7*sqrt(2)Midpoint of AB = a + (b-a/2) = (-2,3) + (7/2,-7/2)= (3/2,-1/2)
this is a continuation of the question... AB=4, BC=6, AE=8, and BE intersects at D
AB and BC are both radii of B. To prove that AB and AC are congruent: "AC and AB are both radii of B." Apex.
Zero.For instance, given a right triangle with points ABC. where AC is the hypotenuse, then to find the angle between AB, we take sin(AB/AC), where AB is the distance between points A and B, and AC is the distance between A and C. If we replace AB with 0, the equation would be sin(0/AC). Sine of zero is always zero.
Find ab
oh my goodness not even dr.sheldon cooper can answer that
ab = sqrt(27) - sqrt(15) = sqrt(3)*3 - sqrt(3)*sqrt(5) = sqrt(3)*(3 - sqrt(5)) and that cannot be simplified further.
B is (-5, 9).
It takes two coordinates to locate one point, but you've given only two numbers to locate two points. The distance between them can't be calculated with the information given, because the points can't be identified.
A & B + respectively
If point a has coordinates (x1,y1), and point b has coordinates (x2, y2), then the slope of the line is given by the formula: m = (y2-y1)/(x2-x1).
The coordinates of point B can be calculated using the midpoint formula. The midpoint formula is used to find the midpoint of two points, and is calculated by taking the average of the x-coordinates and the average of the y-coordinates. In this case, we are given the midpoint of AB, which is (-2, -4). We also know the coordinates of point A, which are (-3, -5). Using the midpoint formula, we can calculate the x-coordinate of point B by taking the average of the x-coordinates of points A and M. This is (-3 + -2)/2 = -2.5. We can calculate the y-coordinate of point B in a similar way. This is (-5 + -4)/2 = -4.5. Therefore, the coordinates of point B are (-2.5, -4.5).
a = (-2,3)b = (5,-4)vector AB = b - a = (7,-7)Length of AB = sqrt( 72 + 72) = sqrt(98) = 7*sqrt(2)Midpoint of AB = a + (b-a/2) = (-2,3) + (7/2,-7/2)= (3/2,-1/2)
Here is a proof. Let a and b be any two real numbers. Consider the number x defined as x = ab + (-a)(b) + (-a)(-b). We can write this out differently as x = ab + (-a)[ (b) + (-b) ] Then, by factoring out -a , we find that x= ab + (-a)(0) = ab + 0 = ab. Also, x = [ a + (-a) ]b + (-a)(-b) And by factoring out b, we find that x=0 * b + (-a)(-b) = 0 + (-a)(-b) = (-a)(-b). Therefore x = ab and x = (-a)(-b) Then, by the transitivity of equality, we have ab = (-a)(-b).
Crossing A genes with B genes can produce offspring with blood types A, B, AB, or O. The A and B genes are codominant, meaning they both express themselves in the AB genotype, while the O gene is recessive to both A and B.
The answer depends on the information that you have about the four points and the manner in which that information is presented. Suppose the 4 points are A, B, C and D and the point that you find is P. If you have the coordinates of A, B, C and D then gradient AP = gradient AB (or any other pair) will suffice. If you have any one of vectors AB (or AC, AD, BC, BD), then vector AP is parallel to vector AB will suffice.