Area of a circle = pi*radius2
Let the sides be abc and their opposite angles be ABC Angle C: (10^2 +11^2 -15^2)/(2*10*11) = 91.04179885 degrees Area: 0.5*10*11*sin(91.04179885) = 54.99090834 Area to the nearest integer = 55 square cm
C = 2 pi r C = 2xpix3cm C = 6pi cm C = 18.8495559 cm
The formual for area is: A = πr2 so the area of circle A (assuming π=3.142) is 28.278cm2, and the area of circle B is 50.272cm2.Their combined area of 78.55cm2 is the area of circle C.The formula for radius is: square root of A/π78.55 ÷ 3.142 = 25, the square root of 25 is 5The radius of circle C is 5cmArea of Circle A = π32 = 9πArea of Circle B = π42 = 16πArea of Circle C = 9π + 16π = 25πLet r = radius of Circle C thenπr2 = 25π : r2 = 25 : r = 5.
C = 20.1 cm
c
A triangle with side a: 7, side b: 7, and side c: 7 cm has an area of 21.22 square cm.
A triangle with side a: 7, side b: 7, and side c: 5 cm has an area of 16.35 square cm.
Let the sides be a b c and their opposite angles be A B C and so:- Using the cosine rule angle A = 57.9 degrees Using the cosine or sine rule angle B = 46.6 degrees Angle C: 180-57.9-46.6 = 75.5 degrees Area: 0.5*6*7*sin(75.5) = 20 square cm rounded
If the circumference of a circle is 7 cm, the radius is 1.114085 cm, which rounds to 1.1 cm
What is the area of the triangle 10cm ,8cm and 6cm
18=c
Using trigonometry its smallest angle is 43.84 degrees and its area is 18.2 square cm--------------------------------------Using the cosine rule to find the angle:a² = b² + c² - 2bc cos A→ cos A = (b² + c² - a²)/(2bc)→ A = arccos ((6.4² + 8.2² - 5.7²)/(2 × 6.4 × 5.7)) ≈ 43.8°Area = ½ × b × c × sin A ≈ ½ × 6.4 cm × 8.2 cm × sin 43.8° ≈ 18.2 cm²
C-5 to the C-7 area of the spinal cord area.
abSinC C being 96 and 7 and 9 being a and b so it would be (7 * 9)*Sin(96) = 62.65487941Improved Answer:-Area of the triangle: 0.5*7*9*sin(96 degrees) = 31.3274397 square cmNote that 96 degrees is the 'included angle' for sides 7 cm and 9 cm because the largest angle of a triangle is opposite its longest side.
A triangle with side a: 2, side b: 2, and side c: 2 cm has an area of 1.73 square cm.
Let its sides be a b c and their opposite angles be A B C and so:- Using the cosine rule angle A = 17.9 degrees Using the cosine rule angle B = 120 degrees Angle C: 180 -17.9 -120 = 42.1 degrees Area: 0.5*48*22*sin(120) = 457 square cm rounded
C = ~37.7 cm A = ~113.1 cm2