Area of a circle = pi*radius2
Oh, what a happy little triangle we have here! To find the area, we can use Heron's formula. First, we find the semi-perimeter by adding all three sides and dividing by 2. Then we plug the values into the formula: Area = √(s(s-a)(s-b)(s-c)), where s is the semi-perimeter, a, b, and c are the sides. Happy painting!
An area is a two dimensional space, made up of length and width. This shape has three dimensions, 10 cm, 5 cm, and 8 cm; this makes it an volume. It has a volume of 10x5x8= 50x8= 400 cm3.
Well, isn't that just a happy little question! To find the area of a circle when given the circumference, you can use the formula A = (C^2) / (4π), where C is the circumference. So, for a circle with a circumference of 50π cm, the area would be (50π)^2 / (4π) = 625π cm². Just imagine all the lovely landscapes you could paint on a canvas that size!
Let the sides be abc and their opposite angles be ABC Angle C: (10^2 +11^2 -15^2)/(2*10*11) = 91.04179885 degrees Area: 0.5*10*11*sin(91.04179885) = 54.99090834 Area to the nearest integer = 55 square cm
C = 2 pi r C = 2xpix3cm C = 6pi cm C = 18.8495559 cm
A triangle with side a: 7, side b: 7, and side c: 7 cm has an area of 21.22 square cm.
A triangle with side a: 7, side b: 7, and side c: 5 cm has an area of 16.35 square cm.
The area of a rectangle is calculated by multiplying its length by its width. If the rectangle measures Cm by Cm, the area would be Cm × Cm, which equals C²m². Therefore, the area of the rectangle is C² square centimeters.
To find the circumference of a circle, you can use the formula ( C = 2\pi r ), where ( r ) is the radius. If the radius is 7 cm, then the circumference is ( C = 2\pi(7) ), which is approximately ( 43.98 ) cm when using ( \pi \approx 3.14 ). If the diameter is 7 cm, the circumference would be ( C = \pi(7) ), approximately ( 21.99 ) cm.
90 centimeters* * * * *That is so wrong!Let the three sides be a, b and c and let s = (a+b+c)/2then area = sqrt[s*(s-a)*(s-b)*(s-c)]So here s = 14.5 cm and so area = sqrt(14.5*2.5*7.5*4.5) = sqrt(1223.4375)= 34.98 sq cm (to 2 dp)
Let the sides be a b c and their opposite angles be A B C and so:- Using the cosine rule angle A = 57.9 degrees Using the cosine or sine rule angle B = 46.6 degrees Angle C: 180-57.9-46.6 = 75.5 degrees Area: 0.5*6*7*sin(75.5) = 20 square cm rounded
If the circumference of a circle is 7 cm, the radius is 1.114085 cm, which rounds to 1.1 cm
To calculate the area of a triangle with side lengths of 11cm, 8cm, and 7cm, we first need to determine the semi-perimeter of the triangle. The semi-perimeter (s) is calculated by adding all three sides together and dividing by 2, so s = (11 + 8 + 7) / 2 = 13 cm. Next, we can use Heron's formula to find the area of the triangle, which is given by the formula: Area = √[s(s-a)(s-b)(s-c)], where a, b, and c are the side lengths. Plugging in the values, we get Area = √[13(13-11)(13-8)(13-7)] = √[1325*6] = √780 ≈ 27.93 cm².
Oh, what a happy little triangle we have here! To find the area, we can use Heron's formula. First, we find the semi-perimeter by adding all three sides and dividing by 2. Then we plug the values into the formula: Area = √(s(s-a)(s-b)(s-c)), where s is the semi-perimeter, a, b, and c are the sides. Happy painting!
18=c
Using trigonometry its smallest angle is 43.84 degrees and its area is 18.2 square cm--------------------------------------Using the cosine rule to find the angle:a² = b² + c² - 2bc cos A→ cos A = (b² + c² - a²)/(2bc)→ A = arccos ((6.4² + 8.2² - 5.7²)/(2 × 6.4 × 5.7)) ≈ 43.8°Area = ½ × b × c × sin A ≈ ½ × 6.4 cm × 8.2 cm × sin 43.8° ≈ 18.2 cm²
The surface area ( A ) of a cube with side length ( s ) is given by the formula ( A = 6s^2 ). The volume ( V ) of the cube is calculated using ( V = s^3 ). If the side length of the cube is ( C ) cm, then the surface area is ( 6C^2 ) cm² and the volume is ( C^3 ) cm³.