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Leaving the answer in terms of pi what is the area of a circle with a circumference of 50 pi cm?
Well, isn't that just a happy little question! To find the area of a circle when given the circumference, you can use the formula A = (C^2) / (4π), where C is the circumference. So, for a circle with a circumference of 50π cm, the area would be (50π)^2 / (4π) = 625π cm². Just imagine all the lovely landscapes you could paint on a canvas that size!
What is the area to the nearest integer of a triangle with dimensions of 10 cm by 11 cm by 15 cm?
Let the sides be abc and their opposite angles be ABC Angle C: (10^2 +11^2 -15^2)/(2*10*11) = 91.04179885 degrees Area: 0.5*10*11*sin(91.04179885) = 54.99090834 Area to the nearest integer = 55 square cm
The circumference of a circle with a radius of 3 centimeters is?
C = 2 pi r C = 2xpix3cm C = 6pi cm C = 18.8495559 cm
What is the length of the circumference of a circle with diameter of 6.2cm?
Remember the circle equation. C = pi *d pi = 3.141592.... d = 6.2 cm Hence C = 3.141592... X 6.2 cm C = 19.7787445.... cm C ~ 19.79 cm To nearest hundredth and 2 d.p.
If circle A has a radius of 3 cm and circle B has a radius of 4 cm and circle C has the same total area as circles A and B combined hoe do you determine the radius of circle C?
The formual for area is: A = πr2 so the area of circle A (assuming π=3.142) is 28.278cm2, and the area of circle B is 50.272cm2.Their combined area of 78.55cm2 is the area of circle C.The formula for radius is: square root of A/π78.55 ÷ 3.142 = 25, the square root of 25 is 5The radius of circle C is 5cmArea of Circle A = π32 = 9πArea of Circle B = π42 = 16πArea of Circle C = 9π + 16π = 25πLet r = radius of Circle C thenπr2 = 25π : r2 = 25 : r = 5.
What is area of equilateral triangle whose side is 7 cm?
A triangle with side a: 7, side b: 7, and side c: 7 cm has an area of 21.22 square cm.
What is the triangles area if the sides are 7cm 7cm and 5cm?
A triangle with side a: 7, side b: 7, and side c: 5 cm has an area of 16.35 square cm.
Area of triangle 12Cm 7Cm 10Cm?
To find the area of a triangle with side lengths 12 cm, 7 cm, and 10 cm, we can use Heron's formula. First, calculate the semi-perimeter of the triangle by adding the three side lengths and dividing by 2: (12 + 7 + 10) / 2 = 29/2 = 14.5 cm. Then, use Heron's formula: Area = √[s(s-a)(s-b)(s-c)], where s is the semi-perimeter and a, b, and c are the side lengths. Plugging in the values, we get Area = √[14.5(14.5-12)(14.5-7)(14.5-10)] = √[14.52.57.5*4.5] = √2446.25 ≈ 49.46 cm².
What are the angles and area of a triangle with dimensions of 7 cm by 6 cm by 8 cm?
Let the sides be a b c and their opposite angles be A B C and so:- Using the cosine rule angle A = 57.9 degrees Using the cosine or sine rule angle B = 46.6 degrees Angle C: 180-57.9-46.6 = 75.5 degrees Area: 0.5*6*7*sin(75.5) = 20 square cm rounded
How doe you find the radius of c equals 7 and round it to the nearest tenth?
If the circumference of a circle is 7 cm, the radius is 1.114085 cm, which rounds to 1.1 cm
What is the area of a triangle with 11cm 8cm 7cm?
What is the area of the triangle 10cm ,8cm and 6cm
If a equals 6 cm what is the area of the equilateral triangle?
18=c
What is the smallest angle and area of a triangle with sides of 6.4 cm by 5.7 cm by 8.2 cm?
Using trigonometry its smallest angle is 43.84 degrees and its area is 18.2 square cm--------------------------------------Using the cosine rule to find the angle:a² = b² + c² - 2bc cos A→ cos A = (b² + c² - a²)/(2bc)→ A = arccos ((6.4² + 8.2² - 5.7²)/(2 × 6.4 × 5.7)) ≈ 43.8°Area = ½ × b × c × sin A ≈ ½ × 6.4 cm × 8.2 cm × sin 43.8° ≈ 18.2 cm²
What is the upper part of the spinal column area?
C-5 to the C-7 area of the spinal cord area.
What is the area of a triangle having dimensions of 7 by 9 by 13 cm whose largest angles is 96 degrees showing and explaining work?
abSinC C being 96 and 7 and 9 being a and b so it would be (7 * 9)*Sin(96) = 62.65487941Improved Answer:-Area of the triangle: 0.5*7*9*sin(96 degrees) = 31.3274397 square cmNote that 96 degrees is the 'included angle' for sides 7 cm and 9 cm because the largest angle of a triangle is opposite its longest side.
Your triangle has sides 2cm long what is its area?
A triangle with side a: 2, side b: 2, and side c: 2 cm has an area of 1.73 square cm.
What is the area and its angles of a triangle with sides of 22 cm by 62 cm by 48 cm?
Let its sides be a b c and their opposite angles be A B C and so:- Using the cosine rule angle A = 17.9 degrees Using the cosine rule angle B = 120 degrees Angle C: 180 -17.9 -120 = 42.1 degrees Area: 0.5*48*22*sin(120) = 457 square cm rounded
