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What is the diagonal of a rectangle 32 ft. by 16 ft.?
Using Pythagoras, Diagonal2 = 322 + 162 = 162*(4 + 1) = 162*5 So diagonal = 16*sqrt(5) = 35.7771 ft (to 4 dp)
How long is a diagonal of a 24 ft x 36 ft rectangle?
43.26661530556787
How long is the diagonal of a rectangle with the dimentions of 12ft by 4ft by 8ft?
The dimensions given appear to describe a rectangular box, with 3 separate pairs of rectangles: 4X8 -> Diagonal is 8.944 ft 4X12 -> Diagonal is 12.649 ft 8X12 -> Diagonal is 14.422 ft
How long is the diagonal of a 24 ft by 30 ft rectangle?
Oh, dude, you're hitting me with the math questions now? Okay, okay, let me think. So, the diagonal of a rectangle can be found using the Pythagorean theorem, right? So, it's like the square root of (24 squared + 30 squared). That's like 36 feet. So, the diagonal of a 24 ft by 30 ft rectangle is 36 feet.
Which has the larger perimeter a 16-foot by 26-foot rectangle or a 20 foot square?
Perimeter of [ 16 x 26 ] rectangle = 16 + 16 + 26 + 26 = 84-ft . Perimeter of a 20-ft square = 4 x 20 = 80-ft . The rectangle has the greater perimeter.
