Let m = 7 and (x1, y1) = (7, 6).
Replace what is given into the slope-point form of the equation of a line:
y - y1 = m(x - x1)
y - 6 = 7(x - 7)
y - 6 = 7x - 49
y - 6 + 6 = 7x - 49 + 6
y = 7x - 43 the lope-intercept form of the equation
y - 7x = 7x - 7x - 43
y - 7x = -43
-7x + y = -43 the general form of the equation
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
Parallel straight line equations have the same slope but with different y intercepts
The equation works out as: y = 5x+7
y = 7
The equation in point slope of the line which passes through -2 -3 and is parallel to 3x plus 2y 10 is y=-1.5x.
sda
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
Point: (2, 17)Slope: 7Equation: y = 2x+13
Y=2x+6
(0,-6) m=-2
Y=mx+b
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
Point: (2, 4) Slope: -3 Equation: y = -3x+10
Yes, I could, if I knew the slope of the line given.
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.