4/8 x 3/5
If 10 out of 26 are girls, then the probability of randomly choosing a boy is 16 out of 26, or 8 out of 13, or about 0.6154.
The probability of choosing 2 girls at random from group of 25 students of which10 are girls and 15 are boys is:P( 2 girls) = (10/25)∙(9/24) = 3/20 = 0.15 = 15%
To find the probability that the second student chosen is a boy given that the first student chosen is a boy, we first note that there are 22 students total (13 girls and 9 boys). If the first student chosen is a boy, there will then be 8 boys and 13 girls remaining, making a total of 21 students left. Therefore, the probability that the second student is a boy is the number of remaining boys (8) divided by the total remaining students (21), which gives us a probability of ( \frac{8}{21} ).
Assuming the choices are made randomly and that the chosen people are not returned to the class, the probability is 77/690 = 0.1116 approx.
The probability is 2 - 6
Probability that a girl is chosen = 23/45 = .511 So, the probability that a boy is chosen = 1 - .511 = .489
The ratio of girls to total students is 15:25, or 3:5. Three out of five students are girls so there would be a 60% probability that a girl would be chosen; a 2 out of 5 chance, or 40% probability that a boy would be chosen.
If 10 out of 26 are girls, then the probability of randomly choosing a boy is 16 out of 26, or 8 out of 13, or about 0.6154.
The probability is 15/25 = 3/5
The probability of choosing 2 girls at random from group of 25 students of which10 are girls and 15 are boys is:P( 2 girls) = (10/25)∙(9/24) = 3/20 = 0.15 = 15%
If the choice is unbiased, the change is 14/(10+14). If the chooser prefers choosing boys, the probability is 0.
The probability is 15/25 = 3/5
14/33
1-30
3-7
1
Assuming the choices are made randomly and that the chosen people are not returned to the class, the probability is 77/690 = 0.1116 approx.