To find the common factor of the terms (6xyz) and (9abx), we first identify the coefficients and the variables. The greatest common factor of the coefficients 6 and 9 is 3. The common variable in both terms is (x). Thus, the factor of (6xyz + 9abx) is (3x), and we can express it as (3x(2yz + 3ab)).
6xyz(3x + 2y + z)
(a + 2b)(a + 2b)
The only factor is 2. 2*(t3 + 2t2 + 4x)
Two is a prime factor of that equation.
You can factor a five out of 15 plus 5x. Therefore, 15 plus 5x factors out to 5(3+x). Hope it helps :)
6xyz(3x + 2y + z)
6xyz(3x + 2y + z)
5m
The other factor is 1.
(a + 2b)(a + 2b)
factor the trinomial 16x^2+24x+9
You can't factor it
That does not factor neatly.
Factor x2 plus 12xp plus 36p2 is (x+6p)(x+6p).
1
No
Not factorable