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(X² + 6x + 16) Since the 6 is positive, you want to find two number that multiply to get 16 and add to get 6. There are none.
You need the quadratic formula: (-b±√(b²-4ac))/2a
(-6±√(36-48))/2
(-6+√-12)/2 (-6-√-12)/2
-3+6i and -3-6i
Both are imaginary numbers, so there are no real solutions. ■
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Earn +20 ptsQ: Factors of x2 plus 6x plus 16?
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-x2 plus 6x plus 16?
-x2 + 6x + 16 = -(x2 - 6x - 16) = -(x - 8)(x + 2) = -(8 - x)(x + 2)
Are the factors for x2 plus 6x plus 5 are x plus 5 and x plus 1?
(X + 5)(X + 1) FOIL this. X2 + 1X + 5X + 5 Gather terms. X2 + 6X + 5 ----------------------------those were the factors
How do you factor 16 plus 6x minus x2?
16 + 6x - x2 = 16 + 8x - 2x - x2 = 8*(2 + x) - x*(2 + x) = (8 - x)*(2 + x)
X2 - 6x - 16?
x2 - 6x - 16 = (x - 8)(x + 2)
How do you Factorise this x2 plus 6x?
x2 + 6x = x*(x + 6)
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