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(X² + 6x + 16) Since the 6 is positive, you want to find two number that multiply to get 16 and add to get 6. There are none.
You need the quadratic formula: (-b±√(b²-4ac))/2a
(-6±√(36-48))/2
(-6+√-12)/2 (-6-√-12)/2
-3+6i and -3-6i
Both are imaginary numbers, so there are no real solutions. ■
What else can I help you with?
-x2 plus 6x plus 16?
-x2 + 6x + 16 = -(x2 - 6x - 16) = -(x - 8)(x + 2) = -(8 - x)(x + 2)
Are the factors for x2 plus 6x plus 5 are x plus 5 and x plus 1?
(X + 5)(X + 1) FOIL this. X2 + 1X + 5X + 5 Gather terms. X2 + 6X + 5 ----------------------------those were the factors
How do you factor 16 plus 6x minus x2?
16 + 6x - x2 = 16 + 8x - 2x - x2 = 8*(2 + x) - x*(2 + x) = (8 - x)*(2 + x)
X2 - 6x - 16?
x2 - 6x - 16 = (x - 8)(x + 2)
How do you Factorise this x2 plus 6x?
x2 + 6x = x*(x + 6)
-x2 plus 6x plus 16?
-x2 + 6x + 16 = -(x2 - 6x - 16) = -(x - 8)(x + 2) = -(8 - x)(x + 2)
Whta are factors of -x2 plus 6x plus 16?
-((x + 2)(x - 8))
What are the solutions for the quadratic equation x2 plus 6x equals 16?
x2 + 6x = 16=> x2 + 6x - 16 = 0=> x2 + 8x -2x - 16 = 0=> (x+8)(x-2) = 0=> x = -8 or x = 2So, the solutions of the quadratic equation x2 + 6x = 16 are -8 and 2.
Are the factors for x2 plus 6x plus 5 are x plus 5 and x plus 1?
(X + 5)(X + 1) FOIL this. X2 + 1X + 5X + 5 Gather terms. X2 + 6X + 5 ----------------------------those were the factors
How do you factor 16 plus 6x minus x2?
16 + 6x - x2 = 16 + 8x - 2x - x2 = 8*(2 + x) - x*(2 + x) = (8 - x)*(2 + x)
X2 - 6x - 16?
x2 - 6x - 16 = (x - 8)(x + 2)
How do you Factorise this x2 plus 6x?
x2 + 6x = x*(x + 6)
Factors x2 minus 6x plus 8?
(x - 4)(x - 2)
How do you factor x2-6x plus 27?
X2 - 6X + 27 = 0 what are the factors of 27 that add to - 6? None! This polynomial is unreal and does not intersect the X axis.
What are the solutions in completing the square x2 plus 6x equals 7?
x2 + 6x = 7 ⇒ x2 + 6x + 9 = 7 + 9 ⇒ (x + 3)2 = 16 ⇒ x + 3 = ±4 ⇒ x = -7 or 1
Factor x2 plus 6x plus 8?
x2 + 6x + 8 = (x + 4)(x + 2)
X3 plus x2 minus 6x plus 4?
x3 + x2 - 6x + 4 = (x - 1)(x2 + 2x - 4)
