Assuming the points are (0,2) and (5,0) and that the "-" is used as a separator rather than as a minus sign. If it is a minus sign, why -0?
Slope = difference in y coordinates/difference in x coordinates
= (2 - 0)/(0 - 5) = 2/(-5) = -0.4
To find the slope of a line passing through two points, use the formula (y2 - y1) / (x2 - x1). In this case, the two points are (17, 101). Since there is only one given point, it is not possible to find the slope of the line passing through these points.
It is a straight line with no slope with a 'y' intercept of 2
Slope, m, equals (y2-y1)/(x2-x1). Slope is (8-2)/(8-2) or 1.
Another set of points are needed to find the slope.
To find the slope of the line that passes through the points (-5, 2) and (2, 3), use the slope formula: ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Here, ( (x_1, y_1) = (-5, 2) ) and ( (x_2, y_2) = (2, 3) ). Plugging in these values gives ( m = \frac{3 - 2}{2 - (-5)} = \frac{1}{7} ). Thus, the slope of the line is ( \frac{1}{7} ).
y=mx+b
1
No
2
1
Not always. For example, try to find the slope of the line that passes through the points (3, 4) and (2, 3).
To find the slope of a line passing through two points, use the formula (y2 - y1) / (x2 - x1). In this case, the two points are (17, 101). Since there is only one given point, it is not possible to find the slope of the line passing through these points.
It is a straight line with no slope with a 'y' intercept of 2
Slope, m, equals (y2-y1)/(x2-x1). Slope is (8-2)/(8-2) or 1.
Slope, m, equals (y2-y1)/(x2-x1). Slope is (0-(-1))/(0-(-1)) or 1/1 or 1.
The slope of a line can be found using the formula: m = (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are two points on the line. For the line that passes through the points A(-2, -1) and B(3, 5), we have: m = (y2 - y1) / (x2 - x1) = (5 - (-1)) / (3 - (-2)) = 6 / 5 = 1.2 So the slope of the line that passes through the points A(-2, -1) and B(3, 5) is 1.2.
It's not possible because the given points would be a vertical line parallel to the y axis