9, 11, and 13
9 + 2(11) + 3(13) = 9 + 22 + 39 = 70
The first integer is 17.
They are 14, 16 and 18.
The let statement is: let the smallest of the three integers be x.
Let x represent the first integer. The second consecutive integer is then x + 1. The equation can be written as x + (x + 1) = 71.
There are no such consecutive integer as is so simple to prove! Suppose the first integer is x. Then the next (consecutive) integer is x+1. Then 2*x + 4*(x+1) = 30 So that 2x + 4x + 4 = 30 6x + 4 = 30 6x = 30 - 4 = 26 x = 26/6 which is NOT an integer.
The first integer is 17.
They are 14, 16 and 18.
Let the first consecutive integer be x. So that:the second integer is x + 1,the third integer is x + 2, andthe fourth integer is x + 3.We have:(x + 1) + (x + 3) = 1322x + 4 = 1322x = 128x = 64 the first integerThus, the four consecutive integers are 64, 65, 66, and 67.
10-11-12
The numbers are 14, 16 and 18.
If the first of these consecutive integers is x, the second integer would be x + 1, and the third integer would be x + 2.Since the sum of the second and the third integer is 17, we can writex + 1 + x + 2 = 172x + 3 = 172x + 3 - 3 = 17 - 32x = 142x/2 = 14/2x = 7Thus, the consecutive integers are 7, 8, and 9.
The let statement is: let the smallest of the three integers be x.
Let x represent the first integer. The second consecutive integer is then x + 1. The equation can be written as x + (x + 1) = 71.
There are no such consecutive integer as is so simple to prove! Suppose the first integer is x. Then the next (consecutive) integer is x+1. Then 2*x + 4*(x+1) = 30 So that 2x + 4x + 4 = 30 6x + 4 = 30 6x = 30 - 4 = 26 x = 26/6 which is NOT an integer.
no solution. If you solve for x (where x is the first integer) the answer is a fraction, which is not an integer.
Let the first integer be x. The second consecutive integer would then be x+1. The sum of these two integers is x + (x+1) = 15. Simplifying, we get 2x + 1 = 15. Solving for x, we find that x = 7. Therefore, the two consecutive integers are 7 and 8.
The integers would begin with 10.