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How can you Write an equation in the form y mx b for the line that has a slope of ¼ and contains the point 12 3?
To write the equation of a line in the form ( y = mx + b ) with a slope of ( \frac{1}{4} ) that passes through the point ( (12, 3) ), start by substituting the slope and the coordinates of the point into the equation. Plugging in ( m = \frac{1}{4} ) and the point ( (12, 3) ):
[ 3 = \frac{1}{4}(12) + b ]
This simplifies to:
[ 3 = 3 + b ]
Solving for ( b ) gives ( b = 0 ). Thus, the equation of the line is:
[ y = \frac{1}{4}x ].
What else can I help you with?
What is the point slope equation of a line with slope -5 that contains the point (63)?
If you mean a slope of -5 and a point of (6, 3) then the equation is y = -5x+33
Write the equation of a line in slope intercept form that has a slope of 2 and contains the point 1 AND 1?
The equation is (y - 1) = 2(x - 1) or, y = 2x - 1
Write the equation in slope intercept form of the line that has a slope of 2 and contains the point (37)?
To write the equation in slope-intercept form (y = mx + b), we start with the slope (m) of 2 and the point (3, 7). We can use the point to find the y-intercept (b). Substituting the point into the equation gives us 7 = 2(3) + b, which simplifies to 7 = 6 + b. Thus, b = 1, and the equation in slope-intercept form is y = 2x + 1.
Write the equation in slope intercept form of the line that has a slope of 2 and contains the point (3,7)?
It is: y-7 = 2(x-3) => y = 2x+1
Write a function represents the line that contains the point 2 and 12 and has a slope of-3?
As a straight line equation: y = -3x+18 in slope intercept form
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point 1 1?
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
Write the equation in slope-intercept form of the line that has a slope of -3 and contains the point -4 5?
The answe iss..... 6
Write the equation in slope intercept form of the line that has a slope of 2 and contains the point 1 1?
y = 2x - 1
Write the equation in slope intercept form of the line that has a slope of 3 and contains the point 2 5?
y=2x+1
Write the equation of a line in slope intercept form that has a slope of 2 and contains the point of 4 2?
It is: y = 2x-6
How do write an equation of a line when given the slope a point of the line?
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
What is the point slope equation of a line with slope -5 that contains the point (63)?
If you mean a slope of -5 and a point of (6, 3) then the equation is y = -5x+33
Write the equation in slopeintercept form of the line that has a slope of 2 and contains the point 3 7?
y = 2x + 1.
Write the equation of a line in slope intercept form that has a slope of 2 and contains the point 1 AND 1?
The equation is (y - 1) = 2(x - 1) or, y = 2x - 1
Write the equation in slope intercept form of the line that has a slope of 2 and contains the point (37)?
To write the equation in slope-intercept form (y = mx + b), we start with the slope (m) of 2 and the point (3, 7). We can use the point to find the y-intercept (b). Substituting the point into the equation gives us 7 = 2(3) + b, which simplifies to 7 = 6 + b. Thus, b = 1, and the equation in slope-intercept form is y = 2x + 1.
What is the point-slope equation of a line with slope-5 that contains the point (6 3)?
Slope: -5 Points: (6, 3) Equation: y = -5x+33
Write the equation in slope intercept form of the line that has a slope of 2 and contains the point (3,7)?
It is: y-7 = 2(x-3) => y = 2x+1
