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How can you take out the area of a right angled triangle?
multiply the base of the triangle by the height then halve the answer.
What is the area of right angled triangle at the right?
There is no right triangle on the right! (Ignore the length of the hypotenuse of a right triangle.) if you have the length of the two legs (base and the upright side): (base x upright) ÷ 2 = area of the right angle triangle.
What is the area of a right angled triangle that is 6 ft wide and 10 ft long?
Area of a right triangle = 1/2 base x height Area = 1/2 10x6 Area = 30
If a triangle has 7cm and 16cm what is the area?
56 cm2 * * * * * Only if these are the shorter legs of a right angled triangle and there is no justification for making that assumption. Two sides of a triangle are not sufficient to determine its area.
Area of an isosceles right angled triangle?
The area of a right angled triangle would be .5 * length *width where the length is the height of the triangle. To find the height of the triangle, take the sine of 45 degrees, which is the degree of the angles other than the 90 degrees, and multiply it by the length of one of the two equal sides. The width of the triangle is the length of the bottom side.
