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Why is it easier to count by 5s or 10s and 2s instead of counting by 3s or 4s?
It is only because we count in tens - and 5 10 and 2 are factors.
What is 3s plus 1?
3s + 1
What is a 3S facility?
3S Facility simply means sales, services and spares
What is 12r-15s-r plus 3s?
12r - 15s - r + 3s = 11r -12s
How do you make four with four 3s?
4=4(3s) 4=12s s= 1/3
What pattern do you see with skip counts by 3s and 10s?
Every 30 numbers you end up in the 10s place when you count by 3s. 30,60,90
There are fewer than 6 dozen egs in a basket If you count them by 3s there are 2 left over Three are left if you count by 5s How many eggs are there?
There are fewer than 6 dozen egs in a basket If you count them by 3s there are 2 left over Three are left if you count by 5s How many eggs are there?
Why is it easier to count by 5s or 10s and 2s instead of counting by 3s or 4s?
It is only because we count in tens - and 5 10 and 2 are factors.
How many 3s in 3333?
Oh, dude, let me grab my calculator for this super challenging math problem. So, in 3333, there are... drumroll... four 3s! Shocking, right? It's like they planned it that way or something.
What is 3s plus 1?
3s + 1
What is 135 equals 3s plus 15?
135=3s +15 120=3s 40=s
how many 3 are in 6037234789333333333333333333333333363?
28 3s
What is a 3S facility?
3S Facility simply means sales, services and spares
How do you do -7 equals 3s-1?
-7 = 3s - 1 +1 +1 (add 1 to both sides to get the variable alone) ___ ____ -6 = 3s __ ___ (-6 and 3s both divided by 3) 3 3 -2 = s
What is 4 3s written as a rational number?
4 3s = 4*3 = 12, which is a rational number.
How do you solve an inequality with a negative coefficient?
The easiest way is to "flip" the inequality symbol end divide by the negative number:Example:6 < 3 - 3s6 - 3 < 3 - 3s -33 < -3s Method a) Divide by negative coefficient and flip the inequality symbol3/-3 > -3s/-3-1 > s or s< -13 < -3s Method b) Full algorithm, eliminate -3s by adding 3s on both sides3 +3s < -3s + 3s3 + 3s < 03 - 3 + 3s < 0 -33s < -33s/3 < -3/3s < -1 Looks familiar? So basically if you perform the full algorithm (method b) you can understand why we flip the inequality symbol when we have to eliminate a negative coefficient but it is faster just to flip the symbol (method a)
Balance 2H2S plus SO2-H2o plus 3s?
2h2s + so2 - 2h20 + 3s
