(x - 1)(x - 14)
(x - 4)(x - 11)
(x - 6)(x - 9)
It's an equation. If you want to solve it for x, you can do so as follows: x2 + 15x = 30 x2 + 15x + (15/2)2 = 30 + (15/2)2 (x + 15/2)2 = 30 + 225/2 x + 15/2 = ± √(285/2) x = (-15 ± √570) / 2
use the quadratic formula since there isn't a factor of 60 that when added together equals 19 The above answer is wrong because 4 and 15 are such numbers. x2 + 19x + 60 = x2 + 4x + 15x + 60 = x(x + 4) + 15(x + 4) = (x + 4)(x + 15)
(x+20)(x-5) x=5 or -20
You can't factor it
(x + 7)(x + 8)
(x-11)(x-4)
(x - 1)(x - 14)
The correct classification of x2 15x is a monomial.
3x2 + 15x + 6 = 3*(x2 + 5x + 2). There are no further rational factors.
x2+15x+14 = (x+1)(x+14)
(x - 4)(x - 11)
(x - 6)(x - 9)
x2 + 15x + 54 = (x + 6)(x + 9) or (x + 9)(x + 6) since 6*9 = 54 and 6 + 9 = 15However, commutativity is implicit in deriving this factorisation so that the two factorisations are the same.or factor by groupingx2 + 15x + 54= x2 + 6x + 9x + 54= (x2 + 6x) + (9x + 54)= x(x + 6) + 9(x + 6)= (x + 6)(x + 9)
x2-15x+54 factor pairs of 54: 1,54 2,27 3,18 6,9 -1,-54 -2,-27 -3,-18 -6,-9 <-6 and -9 sum to -15 x2-6x - 9x+54 x(x-6) - 9(x-6) (x-6)(x-9)