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What is 102a if log2 equals a and log3 equals b?
Find 102a if log2=a and log3=b B has no purpose in this question If a=log2, then 102a =102(log2)
How to solve Log 2 Log 2 Log 2 X equals 0 here 2 is the base not any number?
I guess you mean log2{log2[log2(x)]} = 0 ?Let Y = {log2[log2(x)]}, so you have log2[Y] = 0The solution to this is Y = 1,Then you a simpler equation: log2[log2(x)] = 1Let Z = log2(x), so log2[Z] = 1, solves to Z = 2,so log2(x) = 2, and x = 4
How do you solve log base 2 of 3 to the 1000?
log2(31000) = 1000 log2(3)log2(3) = 1.585 (rounded)1000 log2(3) = log2(31000) = 1,584.96(rounded)
How do you solve log base 2 of x - 3 log base 2 of 5 equals 2 log base 2 of 10?
[log2 (x - 3)](log2 5) = 2log2 10 log2 (x - 3) = 2log2 10/log2 5 log2 (x - 3) = 2(log 10/log 2)/(log5/log 2) log2 (x - 3) = 2(log 10/log 5) log2 (x - 3) = 2(1/log 5) log2 (x - 3) = 2/log 5 x - 3 = 22/log x = 3 + 22/log 5
What is the Log 3 to the base 2?
x = log2(3) is the same as: 2x = 3 You can find it by: log3/log2 = .477/.30 = 1.59 (where log by itself assumes base 10, which most calculators and spreadsheets have built in functions)
What is 102a if log2 equals a and log3 equals b?
Find 102a if log2=a and log3=b B has no purpose in this question If a=log2, then 102a =102(log2)
Given that p equals log2q find an expression in terms of p for log2 routeq and log2 8q?
log2 sqrt(q) = p/2 log2 8q = 3 + p And it is root, not route.
How to solve Log 2 Log 2 Log 2 X equals 0 here 2 is the base not any number?
I guess you mean log2{log2[log2(x)]} = 0 ?Let Y = {log2[log2(x)]}, so you have log2[Y] = 0The solution to this is Y = 1,Then you a simpler equation: log2[log2(x)] = 1Let Z = log2(x), so log2[Z] = 1, solves to Z = 2,so log2(x) = 2, and x = 4
How do you solve log base 2 of 3 to the 1000?
log2(31000) = 1000 log2(3)log2(3) = 1.585 (rounded)1000 log2(3) = log2(31000) = 1,584.96(rounded)
How do you figure how many octaves between 20 hertz and 2560 hertz?
To find out how many octaves are between 20 Hz and 2560 Hz, you can use the formula: Number of octaves = log2(higher frequency / lower frequency). In this case, log2(2560/20) = log2(128) = 7. Therefore, there are 7 octaves between 20 Hz and 2560 Hz.
How do you solve log base 2 of x - 3 log base 2 of 5 equals 2 log base 2 of 10?
[log2 (x - 3)](log2 5) = 2log2 10 log2 (x - 3) = 2log2 10/log2 5 log2 (x - 3) = 2(log 10/log 2)/(log5/log 2) log2 (x - 3) = 2(log 10/log 5) log2 (x - 3) = 2(1/log 5) log2 (x - 3) = 2/log 5 x - 3 = 22/log x = 3 + 22/log 5
What is the Log 3 to the base 2?
x = log2(3) is the same as: 2x = 3 You can find it by: log3/log2 = .477/.30 = 1.59 (where log by itself assumes base 10, which most calculators and spreadsheets have built in functions)
How many octaves between 100 Hz and 6400 Hz?
log2(6400/100) = log2(64) = 6
What is log2 8 equals 3 in exponential form?
log2(8) = 3 means (2)3 = 8
Condense this logarithim log5 plus log2?
log5 +log2 =log(5x2)=log(10)=log10(10)=1
How do you solve log1 plus log2 plus log3?
log1 + log2 + log3 = log(1*2*3) = log6
1 0 - 8 3 - 32 5 - 128?
7Because it is a logarithmic sequence:2^0 =1 so log2 1 = 02^3 = 8 so log2 8 = 32^5 = 32 so log2 32 = 52^7 = 128 so log2 128 = 7
