-- The perimeter is (2 lengths) plus (2 widths).
-- You know the width, so you can subtract it from the perimeter twice.
-- When you do that, the number you have left will be (2 lengths).
-- Surely you can handle it from here.
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Whichever way you choose to solve this problem,
you must also carry out this final step:
-- If your solution is not ' 7 ', then go back to Step-1, rinse, and repeat.
It is impossible to find the perimeter without the width of the rectangle but if you want a formula it would be (43*2) + 2x. x representing the width
Add the length and the width; Double the answer; Job done.
Half perimeter = 109. Subtract 87 and half the answer 22/2 = 11, this is the width. Add on the 87 giving 98, this is the length.
you need length and width length multiply width = area length + length + width + width = perimeter
That would be 3 x 9 inches.
The perimeter of a rectangle = 2 x (length + width) = 2 x (12 + 8) = 2 x 20 = 40 inches
Length of rectangle is 5 inches and its width is 4 inches Check: 2*(5+4) = 18 inches which is its perimeter
Let the width of the rectangle be represented by "w" inches. Since the length is twice the width, it can be expressed as "2w" inches. The formula for the perimeter of a rectangle is P = 2(l + w), where P is the perimeter, l is the length, and w is the width. Substituting the given values into the formula, we get 48 = 2(2w + w). Simplifying, we find that 48 = 6w. Solving for w, we find that the width of the rectangle is 8 inches, and the length is 16 inches.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
Width = 9 inches Length = 30 inches
It is impossible to find the perimeter without the width of the rectangle but if you want a formula it would be (43*2) + 2x. x representing the width
Do-it-in-your-head method: Length + width is half the perimeter which is 27 inches; 27 minus 6 is 21 and one-third of 21 is 7 which is the width. (Length = 2 x 7 + 6 = 20)
Add the length and the width; Double the answer; Job done.
Half perimeter = 109. Subtract 87 and half the answer 22/2 = 11, this is the width. Add on the 87 giving 98, this is the length.
If the rectangle has a width of x inches, and a length of x + 16 inches, then its perimeter equals to 2x + 2x + 32 or 4x + 32. If x = 14, then x + 16 = 30. So the perimeter of rectangle becomes 2(14) + 2(30) = 28 + 60 = 88 inches.
you need length and width length multiply width = area length + length + width + width = perimeter