This algebra lesson explains how to find the slope of a line by looking at its graph. To get from the point (-2, -1) to the point (4, 3), you rise up 4... and run 6.
Assuming the point is (3, -6) and the slope 1, the equation is x - y - 9 = 0
If you mean a slope of -5 and a point of (6, 3) then the equation is y = -5x+33
The straight line equation for a line with a slope of 6 that goes through (1,2) works out as: y = 6x-4
If you mean a slope of 6 and point of (-3, 5) then the equation is: y = 6x+23
This algebra lesson explains how to find the slope of a line by looking at its graph. To get from the point (-2, -1) to the point (4, 3), you rise up 4... and run 6.
Point: (-6, -2) Slope: 5 Equation: y = 5x+28
It is x + 3 = 0.
Slope: -5 Points: (6, 3) Equation: y = -5x+33
Assuming the point is (3, -6) and the slope 1, the equation is x - y - 9 = 0
It is: y = 6x+18 whereas 6 is the slope and 18 is the y intercept
If you mean a slope of -5 and a point of (6, 3) then the equation is y = -5x+33
If you mean: y-2 = 5(x-6) then the point is (6, 2) and the slope is 5
If you mean: y-2 = 5(x-6) then the point is (6, 2) and the slope is 5
The straight line equation for a line with a slope of 6 that goes through (1,2) works out as: y = 6x-4
If you mean a slope of 6 and point of (-3, 5) then the equation is: y = 6x+23
Point slope form of y-7=-3x identifies the line that pass through the slope of line (-2 -5) (7 -6).