Yes it can. A linear equation in the form of y=mx+b can always be graphed used the x and y intercepts.
YES, all linear equations have x-intercepts. because of the x, y has to be there 2!
If there is no y, then the equation is of the form x = c where c is some constant value. And so the line intercepts the x axis at (c,0).
Let us say you X intercepts are -2 and 3 set up (X + 2)(X - 3) FOIL X^2 - X - 6 = 0 ----------------------- your parabolic equation
The roots of the quadratic equation are the x-intercepts of the curve.
Given the linear equation 3x - 2y^6 = 0, the x and y intercepts are found by replacing the x and y with 0. This gives the intercepts of x and y where both = 0.
Yes it can. A linear equation in the form of y=mx+b can always be graphed used the x and y intercepts.
The y-intercept is c in the standard form. The x-intercept is -c/m.
The vertex must be half way between the two x intercepts
YES, all linear equations have x-intercepts. because of the x, y has to be there 2!
If "a" is negative then the graph is a cap. Find the x intercepts. Average the two x intercepts and substitute that into the equation it will give you the y.
If there is no y, then the equation is of the form x = c where c is some constant value. And so the line intercepts the x axis at (c,0).
I believe that you need an equation to solve for the x and y intercepts.
Graph the equation then find the x intercepts.
The 'x' and 'y' intercepts of that equation are both at the origin.
The question does not contain an equation (or inequality) but an expression. An expression cannot have intercepts.
From the equation, the y intercept is simply determined by setting x = 0. The x intercept(s) are generally much harder to find: you will need to find the solutions of y = 0 [or f(x) = 0]. From the graph the intercepts are the coordinates of the points at which the graph crosses the axes.