Yes it can. A linear equation in the form of y=mx+b can always be graphed used the x and y intercepts.
YES, all linear equations have x-intercepts. because of the x, y has to be there 2!
If there is no y, then the equation is of the form x = c where c is some constant value. And so the line intercepts the x axis at (c,0).
Let us say you X intercepts are -2 and 3 set up (X + 2)(X - 3) FOIL X^2 - X - 6 = 0 ----------------------- your parabolic equation
The roots of the quadratic equation are the x-intercepts of the curve.
Given the linear equation 3x - 2y^6 = 0, the x and y intercepts are found by replacing the x and y with 0. This gives the intercepts of x and y where both = 0.
Yes it can. A linear equation in the form of y=mx+b can always be graphed used the x and y intercepts.
The y-intercept is c in the standard form. The x-intercept is -c/m.
The vertex must be half way between the two x intercepts
YES, all linear equations have x-intercepts. because of the x, y has to be there 2!
If "a" is negative then the graph is a cap. Find the x intercepts. Average the two x intercepts and substitute that into the equation it will give you the y.
If there is no y, then the equation is of the form x = c where c is some constant value. And so the line intercepts the x axis at (c,0).
I believe that you need an equation to solve for the x and y intercepts.
Substitute zero for x to find the y-intercept, and substitute zero for y to find the x-intercept.
Graph the equation then find the x intercepts.
The 'x' and 'y' intercepts of that equation are both at the origin.
The question does not contain an equation (or inequality) but an expression. An expression cannot have intercepts.