3
y 2 1 x 0 1 2
y plus 3 1 2x plus 1 can be graphed by first finding the values of Y and X coordinates.
The equation is y=x(x+1)(x-2)2
2y = x + 4Divide each side by 2:y = (1/2)x + 2The graph is a straight line with a slope of (1/2) and a y-intercept of 2.
You move the graph upwards by 2 units.
y=x+1 there for answer is 2
(-1,0)
answer is 1
3
The vertex of the graph Y 3 X-12 plus 2 would be -1/3 and -4/3. This is taught in math.
y 2 1 x 0 1 2
1
y plus 3 1 2x plus 1 can be graphed by first finding the values of Y and X coordinates.
x=1 and x=-7 are.
The equation is y=x(x+1)(x-2)2
The vertex of the graph Y 3 X-12 plus 2 would be -1/3 and -4/3. This is taught in math.