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How do you solve 8x2 plus 16x plus 8 equals 0?
8x2 + 16x + 8 = 0
How do you solve this 15X2-24X12x2 28x?
To solve the expression ( 15X^2 - 24X + 12x + 28x ), first combine the like terms. The terms ( -24X + 12x + 28x ) add up to ( 16X ). Therefore, the expression simplifies to ( 15X^2 + 16X ). If you need to factor it, you can factor out ( X ) to get ( X(15X + 16) ).
What does x equal in 8 - 8x equals 8x plus 18?
8-8x=8x+18 Through simple algebra, this can be manipulated to solve for x: 8=16x+18 -10=16x -5/8=x
How many solutions are in the set 16x plus 2 - 8 equals 16x plus 24?
16x + 2 - 8 = 16x + 24 implies 16x - 6 = 16x + 24 subtracting 16x from both sides, this implies: -6 = 24 So the equation has no soultions.
What is 16x-32?
16x-32 = -16
How do you solve 8x2 plus 16x plus 8 equals 0?
8x2 + 16x + 8 = 0
How do you solve 4x2-16x-32?
8-16x-32=0 8=16x-32 2x-4=0 2x=4 x=2
How do you solve 16x plus 4y equals 8?
You can't solve it. But you can simplify it to get: 4x+y=2
How do you solve x2 plus 16x-80?
x2+16x-80 = 0 (x-4)(x+20) = 0 x = 4 or x = -20
How do you solve for x in 16x equals 4?
Divide by 16, which gives you x=4/16 The 4/16 cancels down to 1/4.
What does x equal in 8 - 8x equals 8x plus 18?
8-8x=8x+18 Through simple algebra, this can be manipulated to solve for x: 8=16x+18 -10=16x -5/8=x
What is 16x 3/5?
16x + 2 - 8 = 16x + 24 implies 16x - 6 = 16x + 24 subtracting 16x from both sides, this implies: -6 = 24 So the equation has no soultions.
How do you solve 16x3-x equals 0?
16x³ - x = 0 By factorization, we obtain: x(16x² - 1) = 0 x(4x - 1)(4x + 1) = 0 Set each term by 0 and solve for x to get: x = 0 and 4x - 1 = 0 and 4x + 1 = 0 x = {0, ±¼}
What is 4x plus 6x plus 6x plus 9?
16x+9 without the rest of the equation, what this equals, I can't solve
How many solutions are in the set 16x plus 2 - 8 equals 16x plus 24?
16x + 2 - 8 = 16x + 24 implies 16x - 6 = 16x + 24 subtracting 16x from both sides, this implies: -6 = 24 So the equation has no soultions.
What is 15x-16x?
15x-16x = -1
What is 16x-32?
16x-32 = -16
